Video Transcript
What can we conclude by applying
the 𝑛th term divergence test in the series the sum of two times the natural log of
𝑛 over three 𝑛 for 𝑛 equals one to infinity?
We begin by recalling that the 𝑛th
term test for divergence says that if the limit as 𝑛 approaches infinity of 𝑎𝑛 is
not equal to zero or does not exist, then the series the sum of 𝑎𝑛 from 𝑛 equals
one to infinity is divergent. And indeed, if that limit is equal
to zero, we can’t tell whether the series converges or diverges and we say that the
test fails.
In our question then, we’re going
to let 𝑎𝑛 be equal to two times the natural log of 𝑛 over three 𝑛. And so our job is to evaluate the
limit as 𝑛 approaches infinity of this expression. If we were to simply apply direct
substitution, then we’d find that our limit is equal to infinity over infinity. And of course, that’s
indeterminate.
So instead, we’re going to recall
L’Hôpital’s rule. This says if the limit as 𝑥
approaches 𝑎 of 𝑓 of 𝑥 over 𝑔 of 𝑥 is equal to infinity over infinity, then the
limit as 𝑥 approaches 𝑎 of 𝑓 prime of 𝑥 over 𝑔 prime of 𝑥 will tell us the value of
the limit as 𝑥 approaches 𝑎 of 𝑓 of 𝑥 over 𝑔 of 𝑥. We can also use this formula if our
limit is equal to zero over zero. But we’re not interested in that
case.
Now of course, we’re working with
𝑛. So we’re going to need to
differentiate two times the natural log of 𝑛 and three 𝑛 with respect to 𝑛. The derivative of the natural log
of 𝑛 is one over 𝑛. So when we differentiate two times
the natural log of 𝑛 with respect 𝑛, we get two over 𝑛. And then the derivative of three 𝑛
is simply three. So we can now evaluate this as 𝑛
approaches infinity.
As 𝑛 gets larger, two over 𝑛 gets
smaller. And as 𝑛 approaches infinity
therefore, two over 𝑛 approaches zero. We find that this is therefore
equal to zero over three, which is zero. And we find that the test fails or
it’s inconclusive.
