Question Video: Finding the Average Rate of Change of a Polynomial Function between Two Points | Nagwa Question Video: Finding the Average Rate of Change of a Polynomial Function between Two Points | Nagwa

# Question Video: Finding the Average Rate of Change of a Polynomial Function between Two Points Mathematics

Suppose a population is π(π‘) = 14π‘Β² + 33,706 as a function of time π‘. What is the average rate of growth of this population when π‘ changes from π‘β to π‘β + β?

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### Video Transcript

Suppose a population is π of π‘ equals 14π‘ squared plus 33,706 as a function of time π‘. What is the average rate of growth of this population when π‘ changes from π‘ sub one to π‘ sub one plus β?

Were being asked to find the average rate of growth of the population, in other words the average rate of change, when π‘ changes from π‘ sub one to π‘ sub one plus β. And so we recall the average rate of change formula. For a continuous function π, the average rate of change over the closed interval π to π is π of π minus π of π over π minus π. Now, our function π of π‘ is defined by 14π‘ squared plus 33,706. And so π of π‘ is in fact a polynomial function. Now, thats really useful because we know that polynomials are continuous over their entire domain. And so were able to use the average rate of change formula.

Were interested in the rate of change of the population when π‘ changes from π‘ sub one to π‘ sub one plus β. So those are our values for π and π. So the average rate of change formula becomes π of π‘ sub one plus β minus π of π‘ sub one all over π‘ sub one plus β minus π‘ sub one. Now, in fact, lets simplify the denominator of our fraction by subtracting π‘ sub one from π‘ sub one. And weβre simply left with β. But what is π of π‘ sub one plus β? Well, we need to replace π‘ in our original function with π‘ sub one plus β. So we get 14π‘ sub one plus β squared plus 33,706.

Now, since it makes a lot of sense to write π‘ sub one plus β squared as π‘ sub one plus β times π‘ sub one plus β, lets do that when we replace π of π‘ sub one plus β in our average rate of change formula. We also know π of π‘ sub one will be 14π‘ sub one squared plus 33,706. And so before we distribute our parentheses, we notice something. When we subtract positive 33,706 from the earlier 33,706, we actually get zero. And so lets go ahead and distribute our parentheses. π‘ sub one times π‘ sub one is π‘ sub one squared. Then, π‘ sub one times β and π‘ sub one times β gives us two π‘ sub one β. And β times β is β squared. So this all simplifies a little bit to get 14 times π‘ sub one squared plus two π‘ sub one β plus β squared minus 14π‘ sub one squared all over β.

And then we distribute the parentheses even further. We multiply each term inside by the 14 on the outside. And we get 14π‘ sub one squared plus 28π‘ sub one β plus 14β squared. And next we notice that 14π‘ sub one squared minus 14π‘ sub one squared is zero. And then we divide each remaining term by the β on the denominator of our fraction. 28π‘ sub one β divided by β is 28π‘ sub one, and 14β squared divided by β is simply 14β. And so that leaves us with 28π‘ sub one plus 14β, which we might choose to write alphabetically as 14β plus 28π‘ sub one. So the average rate of growth of the population as π‘ changes from π‘ sub one to π‘ sub one plus β is 14β plus 28π‘ sub one.