Question Video: Determining the Power of a Given Matrix Mathematics

If 饾惔 = [0, 2 and 2, 0], which of the following is 饾惔鈦光伖? [A] 2鈦光伕 [0, 2 and 2, 0] [B] 2鈦光伖 [0, 2 and 2, 0] [C] 2鹿鈦扳伆 [0, 2 and 2, 0] [D] 2鈦光伕 [1, 0 and 0, 1] [E]2鈦光伖 [1, 0 and 0, 1]

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Video Transcript

If 饾惔 is the two-by-two matrix zero, two, two, zero, which of the following is 饾惔 to the 99th power? Is it option (A) two to the power of 98 multiplied by the two-by-two matrix zero, two, two, zero? Is it option (B) two to the power of 99 multiplied by the two-by-two matrix zero, two, two, zero? Is it option (C) two to the power of 100 multiplied by the two-by-two matrix zero, two, two, zero? Is it option (D) two to the power of 98 multiplied by the two-by-two matrix one, zero, zero, one? Or is it option (E) two to the power of 99 multiplied by the two-by-two matrix one, zero, zero, one?

In this question, we鈥檙e given a two-by-two matrix 饾惔. And we need to determine which of five given expressions represents the matrix 饾惔 to the power of 99. To do this, let鈥檚 start by recalling what it means to raise a matrix to an exponent. If 饾惔 is a square matrix and the exponent is a positive integer, then this means we multiply the matrix by itself where the number of times 饾惔 appears in the product is equal to the exponent. In particular, if the exponent is one, then our matrix is just equal to itself. And when the exponent is 99, we need to multiply 饾惔 by itself where 饾惔 appears in the product 99 times.

Of course, working out this product directly would be very difficult. This is a product with 99 two-by-two matrices. Instead, let鈥檚 try and find a pattern that this product follows. We鈥檒l do this by using the associativity property of matrix multiplication. Let鈥檚 just find 饾惔 squared. And remember, 饾惔 squared is 饾惔 multiplied by 饾惔. That鈥檚 the two-by-two matrix zero, two, two, zero multiplied by the matrix zero, two, two, zero.

Recall to multiply two matrices together, we need to find the sum of the products of the rows of the first matrix and the columns of the second matrix. So the element in row one, column one of the product of these two matrices will be the product of the elements of the first row in the first matrix and the first column in the second matrix. That鈥檚 zero multiplied by zero plus two multiplied by two, which we can calculate is equal to four. So the entry in row one, column one of 饾惔 squared is four. We can then do the same for the element in row one, column two. We need to multiply zero by two and then add on to this the product of two and zero. And both of these terms have a factor of zero. So the answer is zero.

We get a very similar story in the entry in row one, column two of our matrix. It鈥檚 equal to two times zero plus zero times two which is equal to zero. Finally, we can calculate the element in row two, column two. It鈥檚 equal to two times two plus zero times zero, which we can calculate is equal to four. Therefore, the matrix 饾惔 squared is the two-by-two matrix four, zero, zero, four. And this is a very useful result because we can see this is very similar to the identity matrix of order two. In particular, if we take a scale factor of four outside of this matrix, we can see that 饾惔 squared is equal to four multiplied by the identity matrix of order two. And this is a very useful result because multiplying a matrix by the identity matrix is very easy to calculate.

We can use this to simplify our expression for 饾惔 to the power of 99. To do this, we鈥檙e going to use the associativity of matrix multiplication. This will allow us to replace any product of 饾惔 and 饾惔 with 饾惔 squared. And we have to note there are only 99 factors of 饾惔 in this expression. This is an odd number. So when we rewrite these factors of 饾惔 times 饾惔 as 饾惔 squared, we will only have 49 pairs of this form and one last factor of 饾惔. And before we start evaluating this expression, there鈥檚 one thing worth noting. We can write the factor of 饾惔 anywhere in this expression. And this is because we can choose the 49 pairs of 饾惔 times 饾惔 in any way we want and this doesn鈥檛 matter. It won鈥檛 change the final answer of our question.

We鈥檙e now ready to evaluate this expression. We鈥檒l do this by substituting 饾惔 squared is equal to four multiplied by the two-by-two identity matrix into this expression. Doing this gives us 49 factors of four multiplied by the identity matrix of order two and then we multiply by 饾惔. And now we can simplify this expression. Let鈥檚 start with the scalar factors. We have 49 factors of four, which simplifies to four to the power of 49. Next, we have 49 factors of the identity matrix multiplied by 饾惔. But remember, multiplying a matrix by the identity matrix doesn鈥檛 change its value. So this is just equal to 饾惔.

Therefore, we鈥檝e shown that 饾惔 to the power of 99 is four to the power of 49 multiplied by 饾惔. And this is not any of our options. Instead, we need to simplify slightly. We need to write our scalar factor as a power of two, and we can do this by using the laws of exponents. Four is two squared, and two squared all raised to the power of 49 is two to the power of two times 49 which is two to the power of 98. Substituting this into our expression and writing our matrix 饾惔 out in four gives us our final answer. If 饾惔 is the two-by-two matrix zero, two, two, zero, then 饾惔 to the power of 99 is equal to two to the power of 98 multiplied by 饾惔, which is option (A).

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