### Video Transcript

A man weighs 97 and four-fifths of
a kilogram on Earth, and his weight on the Moon is one-sixth of its value on
Earth. Find the man’s weight on the
Moon.

We are given the man’s weight on
Earth, and we are told that on the Moon it is one-sixth of this. We therefore need to multiply 97
and four-fifths by one-sixth. Our first step is to convert the
mixed number 97 and four-fifths into an improper or top-heavy fraction. We do this firstly by multiplying
97 by five, which gives us 485. We then add the numerator to this,
giving us 489. 97 and four-fifths is equal to four
hundred and eighty-nine fifths.

When multiplying two fractions, we
need to multiply the numerators and separately the denominators. We can cross cancel first, though,
as six and 489 are both divisible by three. Six divided by three is two, and
489 divided by three is 163 as shown in the bus stop short division method. Multiplying the numerators gives us
163, and multiplying the denominators gives us 10. We can now convert this improper
fraction back into a mixed number by dividing the numerator by the denominator. 163 divided by 10 is equal to 16
remainder three. Therefore, 163 over 10 is the same
as 16 and three-tenths. The man’s weight on the Moon is 16
and three-tenths of a kilogram. This could also be written in
decimal form as 16.3 kilograms.