Question Video: Acceleration and Force | Nagwa Question Video: Acceleration and Force | Nagwa

Question Video: Acceleration and Force Physics • First Year of Secondary School

A cup of mass 125 g is at rest on a desk when it is accidentally knocked by a person’s arm. The cup accelerates in the direction that it is pushed at a rate of 0.25 m/s². How much force is applied by the arm that knocks the cup? Give your answer to two decimal places.

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Video Transcript

A cup of mass 125 grams is at rest on a desk when it is accidentally knocked by a person’s arm. The cup accelerates in the direction that it is pushed at a rate of 0.25 meters per second squared. How much force is applied by the arm that knocks the cup? Give your answer to two decimal places.

Okay, so in this question, we know that we’ve got a cup which has a mass of 125 grams, and initially it’s at rest on a desk. We know that this cup is then knocked by a person’s arm, applying some force to it, which causes it to accelerate in the direction it is pushed. We’re told that the acceleration has a magnitude of 0.25 meters per second squared. We need to work out the amount of force, which we’ve labeled 𝐅, applied by the arm which knocks the cup.

To solve this question, we’ll need to find a relationship between the acceleration of the cup, 𝑎, the force exerted on the cup, 𝐅, and the cup’s mass, 𝑚. This relationship is Newton’s second law of motion, which says that the force 𝐅 applied to an object is equal to the object’s mass, 𝑚, multiplied by the acceleration, 𝑎, that the object experiences. Since in this case we know the values of 𝑚 and 𝑎, we can use this equation from Newton’s second law in order to work out the force applied to the cup. Before we do this, though, we need to consider the units of the quantities.

If we want to find the force in newtons, which is the standard SI unit of force, then we need to have the mass and the acceleration in their standard units as well. The standard unit of mass is the kilogram, and the standard unit of acceleration is meters per second squared. Our value for the acceleration, 𝑎, of the cup already has units of meters per second squared. However, the mass, 𝑚, is in units of grams rather than kilograms. We therefore need to convert this value from grams into kilograms. Let’s recall that one kilogram is equal to 1000 grams. Dividing both sides of this equation by 1000, we see that one gram is equal to one thousandth of a kilogram. So to convert this mass 𝑚 from grams into kilograms, we need to multiply it by one over 1000 kilograms per gram. We find then that the mass of the cup is 0.125 kilograms.

We are now ready to take our values for the mass, 𝑚, and acceleration, 𝑎, and substitute them into this equation for the force, 𝐅. We have that 𝐅 is equal to 0.125 kilograms multiplied by 0.25 meters per second squared. Evaluating this gives a force of 0.03125 newtons. Notice though that we’re asked to give our answer to two decimal places. To two decimal places, our result rounds down to 0.03 newtons.

Our final answer then is that the force applied by the arm that knocks the cup is 0.03 newtons.

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