# Question Video: Using Unit Rate to Compare Elements Mathematics • 6th Grade

Michael is selling tickets for a charity football game. The table shows the number of tickets purchased and the total price paid for three different people. Which person paid the lowest price per ticket? [A] A [B] B [C] C

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### Video Transcript

Michael is selling tickets for a charity football game. The table shows the number of tickets purchased and the total price paid for three different people. Which person paid the lowest price per ticket?

In order to calculate the price per ticket, we need to divide the total price by the number of tickets purchased. For person A, we need to divide 127 by two. If we didn’t have a calculator, one way to solve this would be using the bus stop method. Two doesn’t divide into one, but two divides into 12 six times. There are three twos in seven and we have one remainder. So we carry a one to the tenths column.

When dividing by an integer, we need to keep the decimal point in line. 10 divided by two is equal to five, and zero divided by two is equal to zero. This means that the cost per ticket for person A is 63 dollars and 50 cents. For person B, we need to divide 247 by four as they paid a total price of 247 dollars and bought four tickets. 24 divided by four is equal to six. Seven divided by four is equal to one, remainder three. 30 divided by four is equal to seven, remainder two. And finally, 20 divided by four is equal to five.

This means that the cost per ticket for person B was 61 dollars and 75 cents. Person C paid a total price of 326 dollars, and they bought six tickets. We therefore need to divide 326 by six. Using the same method, we get an answer of 54 dollars and 33 cents to two decimal places. The answer is actually 54.3 recurring. But as we’re dealing with money, we need our answer to two decimal places.

The smallest number in the table is 54.33. Therefore, we can say that person C paid the lowest price per ticket.