Video Transcript
Given a complex number π§, where the principal argument of π§ is π equals 11π over 12, determine the principal argument of 10π§.
Remember, the argument of a complex number describes the angle that the line segment joining the complex number to the origin makes with the positive real axis. Since this is measured in a counterclockwise direction, an argument of 11π over 12 radians will correspond to a complex number plotted in the second quadrant. So what do we mean when we talk about the principle argument of a complex number? The principal argument of a complex number is restricted to the open-closed interval negative π to π radians. So given any argument, specifically one thatβs greater than π or less than negative π, we can add or subtract multiples of two π to ensure that our argument is within the range for the principal argument.
Now weβre told that the principle argument of π§ is 11π over 12. But what does that mean for the principal argument of 10π§? Letβs begin by looking at an algebraic method, and then weβll consider a geometric representation. Letβs imagine weβre given the complex number in exponential form: π§ equals ππ to the ππ. Now here π is the argument and π is the magnitude or modulus of the complex number. This simply represents the distance that the point lies on the complex plane from the origin. What happens when we multiply this complex number by 10? We multiply the entire expression ππ to the power of ππ by 10. So 10π§ is 10ππ to the power of ππ.
We notice the value of π remains unchanged by multiplying the entire expression by 10. So if the argument of the complex number π§ is some value π, then multiplying the entire expression by a constant does not change the argument. So the argument of 10π§ is 11π over 12. Now this makes a lot of sense if we think about this geometrically. Imagine we were to plot the complex number 10π§ on the complex plane. This essentially is a dilation on the complex plane by a scale factor of 10. This does not affect the argument and it just affects the magnitude or modulus of our complex number. Either way, we showed that the argument of 10π§ is 11π over 12.