Question Video: Calculating the Maximum Wavelength of Photoelectrons | Nagwa Question Video: Calculating the Maximum Wavelength of Photoelectrons | Nagwa

Question Video: Calculating the Maximum Wavelength of Photoelectrons Physics • Third Year of Secondary School

For a metal surface that has a work function of 2.5 eV, the maximum wavelength for light to enable emitting photoelectrons from this surface is _. You can use ℎ = 6.625 × 10⁻³⁴ J⋅s and 𝑐 = 3 × 10⁸ m/s.

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Video Transcript

For a metal surface that has a work function of 2.5 electron volts, the maximum wavelength for light to enable emitting photoelectrons from this surface is blank. You can use ℎ equals 6.625 times 10 to the power of negative 34 joule seconds and 𝑐 equals three times 10 to the power of eight meters per second.

Let’s begin by recalling that the work function of a metal tells the minimum amount of energy needed to remove an electron from its surface. Thus, in order to induce the photoelectric effect, an incident photon must have energy that is greater than or equal to the work function of a given surface. Also, recall that the energy of a photon is given by ℎ, the Planck constant, times 𝑐, the speed of light, divided by 𝜆, the photon’s wavelength.

Since we want to solve for the maximum photon wavelength, we’re solving for the minimum photon energy. So, in this case, we should set ℎ𝑐 over 𝜆 equal to the work function 𝑊. Let’s now rearrange the formula to make wavelength the subject. To do this, we just need to multiply both sides by 𝜆 over 𝑊. And so the expression becomes 𝜆 equals ℎ𝑐 over 𝑊.

But before we substitute in values for all these terms on the right-hand side, let’s make sure they’re expressed in appropriate SI or SI-derived units. ℎ and 𝑐 are good to go, but notice that the work function is currently given in electron volts. So we should convert it into joules. To do this, we need to remember that one electron volt equals 1.60 times 10 to the power of negative 19 joules. And so we can multiply the work function value by this conversion factor, which itself is just equal to one. Multiplying through and canceling out units of electron volts, we get that 𝑊 equals 4.0 times 10 to the power of negative 19 joules.

Finally, we’re ready to substitute the work function, the Planck constant, and the speed of light into the formula for wavelength. Doing this and grabbing a calculator, we get a result of 4.97 times 10 to the power of negative seven meters. And we have our final answer. This is the maximum wavelength of light that will induce the photoelectric effect on this metal surface.

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