Question Video: Simplifying Trigonometric Expressions Using a Shift and Reciprocal Identities | Nagwa Question Video: Simplifying Trigonometric Expressions Using a Shift and Reciprocal Identities | Nagwa

Question Video: Simplifying Trigonometric Expressions Using a Shift and Reciprocal Identities Mathematics

Simplify sec ((πœ‹/2) βˆ’ πœƒ)/cot (πœ‹ βˆ’ πœƒ).

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Video Transcript

Simplify the sec of πœ‹ over two minus πœƒ over cot of πœ‹ minus πœƒ.

In this expression, we have a reciprocal function divided by a reciprocal function. Additionally, we have a cofunction identity and a correlated identity. First, the sec of πœ‹ over two minus πœƒ equals the csc of πœƒ. And second, the cot of πœ‹ minus πœƒ equals the negative cot of πœƒ. We rewrite sec of πœ‹ over two minus πœƒ as csc πœƒ. And the cot of πœ‹ minus πœƒ becomes the negative cotangent. And then we’ll recall that our reciprocal functions csc πœƒ equals one over sin πœƒ, cot πœƒ equals cos πœƒ over sin πœƒ.

We’re using a strategy to take all of our reciprocal functions and write them in terms of sine and cosine, which gives us one over sin πœƒ divided by negative cos πœƒ over sin πœƒ. Dividing by a fraction is multiplying by its reciprocal. A sine in the denominator and a sine in the numerator cancel each other out, which equals negative one over cos πœƒ, which means we’ll need to use one final identity sec πœƒ equals one over cos πœƒ, which makes the simplified form negative sec πœƒ.

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