Question Video: Forming and Solving Quadratic Equations | Nagwa Question Video: Forming and Solving Quadratic Equations | Nagwa

Question Video: Forming and Solving Quadratic Equations Mathematics • Third Year of Preparatory School

Find the positive number which is 66 less than twice its square.

05:31

Video Transcript

Find the positive number which is 66 less than twice its square.

To answer this question, we’re going to need to use some algebra, and we’re going to need to form an equation. So let’s introduce a letter to represent this positive number. We can call it whatever we like; let’s call it 𝑥. We’re told that 𝑥 is 66 less than twice its square. Now, the square of 𝑥 can be written as 𝑥 squared. Twice its square means we’re multiplying this by two, so that gives two 𝑥 squared. And we then want 66 less than this value. So we have the expression two 𝑥 squared minus 66. But remember, this is equal to the number itself. So as an equation, we have two 𝑥 squared minus 66 is equal to 𝑥. We’ve therefore formulated this problem as a quadratic equation. And we now need to solve it in order to find the value of 𝑥.

We want to collect all of the terms on the same side of the equation. Which we can do by subtracting 𝑥 from each side, giving two 𝑥 squared minus 𝑥 minus 66 equals zero, which is a quadratic equation in its most easily recognizable form. Now, we want to solve this quadratic equation by factoring. But notice that the coefficient of 𝑥 squared, the leading coefficient, is not equal to one. So we’re going to use the method of factoring by grouping. We look for two numbers whose sum is the coefficient of 𝑥, that’s negative one, and whose product is the product of the coefficient of 𝑥 squared and the constant term. That’s two times negative 66 which is negative 132.

The more familiar you are with your times tables, the more quickly you’ll spot these two numbers. They’re negative 12 and positive 11. Now, the next step may look a little strange. What we’re going to do is take that term of negative 𝑥 and rewrite it using these two numbers. We’re going to rewrite it as negative 12𝑥 plus 11𝑥. So we now have our quadratic equation with four terms, two 𝑥 squared minus 12𝑥 plus 11𝑥 minus 66 is equal to zero. Next, what we’re going to do is split this quadratic equation in half. And we’re going to factor the two halves separately.

Looking at the first half, two 𝑥 squared minus 12𝑥, these two terms have a common factor of two 𝑥. And if we take this out, we’re then left with 𝑥 minus six. So the first half factors as two 𝑥 multiplied by 𝑥 minus six. Looking at the second half of our quadratic, 11𝑥 minus 66, these two terms have a common factor of 11. And once we’ve factored by 11, we’re left with 𝑥 minus six inside the parentheses. So the second half of our quadratic factorizes as 11 multiplied by 𝑥 minus six.

Now, the key point, and this will always be the case if a quadratic equation can be solved by factoring, is that the two halves of our expression now have a common factor of 𝑥 minus six. We therefore factor the entire quadratic by 𝑥 minus six. For the first term, we have to multiply by two 𝑥. And for the second, we have to multiply by positive 11. So our quadratic can be written as 𝑥 minus six multiplied by two 𝑥 plus 11. And it’s now in a fully factored form. Remember, it will always be the case that the two halves of your expression share a common factor if the quadratic equation can be factored.

If you go through this method and you find the two halves don’t share a common factor, then you’ve either made a mistake or the quadratic equation you’re working with can’t actually be factored. And you need to use another method to solve it such as the quadratic formula or completing the square, if you’re aware of these. Anyway, our quadratic equation can be factored, and we have its factored form. So the next step is to take each factor in turn and set them equal to zero.

We have 𝑥 minus six equals zero or two 𝑥 plus 11 equals zero. To solve the first equation, we need to add six to each side, giving 𝑥 equals six. And we can solve the second equation in two steps. First, we subtract 11 from each side, giving two 𝑥 equals negative 11. And then, we can divide by two, giving 𝑥 equals negative 11 over two or negative 5.5. Now, both of these are valid solutions to our quadratic equation. But if we look back at the question, we were told that this number that we’re looking for must be positive. Which means it can’t be equal to negative 11 over two. So we can eliminate this value. Our solution, then, is that 𝑥 is equal to six. But let’s check this.

This number needs to be 66 less than twice its square, so we have two times six squared minus 66. That’s two times 36 which is 72 minus 66 which is indeed equal to six, the number itself. So this confirms that our solution is correct. So we have our answer to the problem. The positive number we’re looking for is six.

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