Question Video: Second Derivative Test for a Function | Nagwa Question Video: Second Derivative Test for a Function | Nagwa

Question Video: Second Derivative Test for a Function Mathematics • Third Year of Secondary School

Suppose 𝑓′(4) = 0 and 𝑓″(4) = −4. What can you say about 𝑓 at the point 𝑥 = 4? [A] 𝑓 has a local minimum at 𝑥 = 4. [B] 𝑓 has a local maximum at 𝑥 = 4. [C] 𝑓 has a point of inflection at 𝑥 = 4. [D] It is not possible to state the nature of the turning point of 𝑓 at 𝑥 = 4. [E] 𝑓 has a vertical tangent at 𝑥 = 4.

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Video Transcript

Suppose 𝑓 prime of four equals zero and 𝑓 double prime of four equals negative four. What can you say about 𝑓 at the point 𝑥 equals four? 𝑓 has a local minimum at 𝑥 equals four. 𝑓 has a local maximum at 𝑥 equals four. 𝑓 has a point of inflection at 𝑥 equals four. It is not possible to state the nature of the turning point of 𝑓 at 𝑥 equals four. Or 𝑓 has a vertical tangent at 𝑥 equals four.

Let’s take each of the pieces of information we’ve been given in turn. Firstly, we’re told that 𝑓 prime of four is equal to zero. And if the first derivative of a function is equal to zero at a given point, then the function has a critical point at that point. So we know that 𝑓 has a critical point when 𝑥 is equal to four. Next, we’re told that 𝑓 double prime of four is equal to negative four. So the second derivative of our function 𝑓 is negative when 𝑥 is equal to four. The second derivative will be negative at a local maximum. So we can conclude that 𝑓 has a local maximum at 𝑥 equals four.

That’s the second option in the list we’ve been given. The first, third, and fourth options are therefore false. If a point is a local maximum, it can’t also be a local minimum or a point of inflection. And it has been possible for us to determine the nature of this turning point. Let’s consider the fifth option. We know that the first derivative of our function 𝑓 is zero when 𝑥 is equal to four, which means that the slope of the curve and the slope of the tangent will be zero. Therefore, 𝑓 will have a horizontal, not a vertical tangent at 𝑥 equals four. So we’ve completed the problem. 𝑓 has a local maximum at 𝑥 equals four.

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