Question Video: Using Proportions to Simplify an Expression | Nagwa Question Video: Using Proportions to Simplify an Expression | Nagwa

Question Video: Using Proportions to Simplify an Expression Mathematics • Third Year of Preparatory School

If 𝑎, 𝑏, 𝑐, and 𝑑 are proportional, which of the following equals √((6𝑎² − 9𝑏²)/(6𝑐² − 9𝑑²))? [A] 𝑑/𝑏 [B] 𝑎/𝑑 [C] 𝑐/𝑎 [D] 𝑎/𝑐

02:45

Video Transcript

If 𝑎, 𝑏, 𝑐, and 𝑑 are proportional, which of the following equals the square root of six 𝑎 squared minus nine 𝑏 squared over six 𝑐 squared minus nine 𝑑 squared? Is it option (A) 𝑑 over 𝑏, option (B) 𝑎 over 𝑑, option (C) 𝑐 over 𝑎, or option (D) 𝑎 over 𝑐?

We’re told that 𝑎, 𝑏, 𝑐, and 𝑑 are proportional, so let’s begin by considering what this means. We can write this as 𝑎 is to 𝑏 as 𝑐 is to 𝑑. And we note that 𝑎 and 𝑑 are known as the extremes and 𝑏 and 𝑐 are the means or the middle terms. Now we can also write this as 𝑎 over 𝑏 is the same as 𝑐 over 𝑑; that is, the proportion of 𝑎 to 𝑏 is equal to that of 𝑐 two 𝑑. And now if 𝑎 is in the same proportion to 𝑏 as 𝑐 is to 𝑑, we can say that for some constant 𝑝, 𝑎 multiplied by 𝑝 is equal to 𝑏 and 𝑐 multiplied by 𝑝 is equal to 𝑑.

And now squaring both sides of our first equation, we have 𝑎 squared 𝑝 squared is equal to 𝑏 squared. And squaring both sides of our second equation gives us 𝑐 squared 𝑝 squared is equal to 𝑑 squared. And so we have 𝑏 squared in terms of 𝑎 squared and 𝑑 squared in terms of 𝑐 squared. So now let’s look at the given expression. Inside our square root, we have six 𝑎 squared minus nine 𝑏 squared over six 𝑐 squared minus nine 𝑑 squared. We could at this point simplify this slightly by noting that in both the numerator and denominator, we have a common factor of three. And taking this outside some parentheses, we could eliminate this three. But in fact, we may as well leave it as it is since, as we’ll see, it’s going to cancel anyway.

The more important thing to note is that we can substitute our expressions for 𝑏 squared and 𝑑 squared in terms of 𝑎 squared and 𝑐 squared into the given expression. So now inside our square root, we have six 𝑎 squared minus nine 𝑎 squared 𝑝 squared over six 𝑐 squared minus nine 𝑐 squared 𝑝 squared. And now we see we have a common factor of 𝑎 squared in our numerator and 𝑐 squared in our denominator. And taking these outside parentheses, we see that we have a common factor of six minus nine 𝑝 squared in the numerator and the denominator.

So now dividing numerator and denominator by six minus nine 𝑝 squared, we’re left with the square root of 𝑎 squared over 𝑐 squared. And recalling that the square root of a fraction is the square root of the numerator over the square root of the denominator, we have the square root of 𝑎 squared over the square root of 𝑐 squared. And now recalling that the square root of the square of the number is simply the number, we’re left with 𝑎 over 𝑐. If 𝑎, 𝑏, 𝑐, and 𝑑 are proportional then, the given expression is equal to option (D), and that’s 𝑎 over 𝑐.

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