Question Video: Identifying the Diagram That Correctly Labels the Oxidizing and Reducing Agents in a Chemical Equation | Nagwa Question Video: Identifying the Diagram That Correctly Labels the Oxidizing and Reducing Agents in a Chemical Equation | Nagwa

Question Video: Identifying the Diagram That Correctly Labels the Oxidizing and Reducing Agents in a Chemical Equation Science • Third Year of Preparatory School

The equation CuO (s) + H₂ (g) ⟶ Cu (s) + H₂O (l), shows how copper oxide can be reacted with hydrogen to produce copper and water. Which of the following images correctly identifies the oxidizing and reducing agents in this chemical equation? [A] Image A [B] Image B [C] Image C [D] Image D [E] Image E

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Video Transcript

The equation CuO solid plus H2 gas reacts to form Cu solid plus H2O liquid shows how copper oxide can be reacted with hydrogen to produce copper and water. Which of the following images correctly identifies the oxidizing and reducing agents in this chemical equation?

In this question, we are given a selection of chemical equations showing the reaction between copper(II) oxide and hydrogen gas. In each of the different answer options, we can see that one of the products or reactants is labeled as an oxidizing agent and a second product or reactant is labeled as a reducing agent. Let’s clear some space to discuss the processes of oxidization and reduction.

It is possible to explain oxidization and reduction in chemical reactions in a number of different ways. For example, we could describe oxidization as the addition of oxygen or the loss of hydrogen by a substance. We could describe reduction as the loss of oxygen or the gain of hydrogen by a substance. It’s also possible for us to describe oxidization and reduction in terms of electrons being gained or lost. However, with the reaction equation provided, it’ll be easier for us to use the gain or loss of oxygen to answer this question.

When identifying which substance in a reaction is an oxidizing agent and which is a reducing agent, we are referring to the reactants. A reactant that oxidizes another reactant is known as an oxidizing agent. On the other hand, a reactant that reduces another reactant is a reducing agent. If we look at the reaction between copper(II) oxide and hydrogen gas, we can see that copper(II) oxide loses oxygen to form elemental copper and is therefore reduced. This means that hydrogen gas, or H2, must be the reducing agent.

If we were to look at this from a different point of view, we might say that hydrogen gains oxygen and is oxidized to become water. Because hydrogen is oxidized, copper(II) oxide must be the oxidizing agent. Oxidization and reduction cannot occur independently. And so it is always the case that when one happens, the other will happen as well.

Let’s bring the answer choices back up on the screen to determine the correct answer. Now that we know that oxidizing and reducing agents are reactants, we can eliminate answer choices (B), (C), and (D), because these answer choices have one or more products labeled as oxidizing or reducing agents. We can also eliminate answer choice (E) because the oxidizing and reducing agent labels of the reactants in this answer choice are reversed.

We can see in answer choice (A) that copper(II) oxide is labeled as the oxidizing agent and hydrogen is labeled as the reducing agent. Therefore, the correct answer is answer choice (A).

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