Question Video: Finding the Solution Set of a Quadratic Equation | Nagwa Question Video: Finding the Solution Set of a Quadratic Equation | Nagwa

Question Video: Finding the Solution Set of a Quadratic Equation Mathematics • First Year of Secondary School

Find the solution set of the equation 𝑥² = 3𝑥 + 10.

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Video Transcript

Find the solution set of the equation 𝑥 squared is equal to three 𝑥 plus 10.

As we have been asked to find the solution set of the equation 𝑥 squared is equal to three 𝑥 plus 10, we must first rearrange it into the form 𝑓 of 𝑥 is equal to zero. Note that we can do this by subtracting three 𝑥 and 10 from both sides to get 𝑥 squared minus three 𝑥 minus 10 equals zero. Recall that the solutions of the equation 𝑓 of 𝑥 equals zero are the 𝑥-values of the points where the graph of the function crosses the 𝑥-axis. We can find these values by sketching the graph of the function 𝑓 of 𝑥 equals 𝑥 squared minus three 𝑥 minus 10 and finding where it crosses the 𝑥-axis.

We can draw the graph by setting up a table of values and calculating 𝑓 of 𝑥 for the selected 𝑥-values. Taking values of 𝑥 from negative three to six, we have the given values of 𝑓 of 𝑥. We can then plot these on the 𝑥𝑦-plane and join them with a smooth curve. It is easily seen that the curve crosses the 𝑥-axis at 𝑥 equals five and 𝑥 equals negative two. Note that we could have read off these values directly from our table, which showed that 𝑓 of 𝑥 equals zero for these two values of 𝑥. We conclude that the solution set of the equation 𝑥 squared is equal to three 𝑥 plus 10 is negative two, five.

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