Question Video: Identifying Which Equation Shows the Reaction at a Hydrogen Fuel Cell Cathode under Alkaline Conditions | Nagwa Question Video: Identifying Which Equation Shows the Reaction at a Hydrogen Fuel Cell Cathode under Alkaline Conditions | Nagwa

Question Video: Identifying Which Equation Shows the Reaction at a Hydrogen Fuel Cell Cathode under Alkaline Conditions Chemistry • Third Year of Secondary School

Which of the following equations shows the reaction at the cathode of a hydrogen fuel cell under alkaline conditions? [A] 2 H₂(g) ⟶ 4 H⁺(aq) + 4 e⁻ [B] O₂(g) + 4 H⁺(aq) + 4 e⁻ ⟶ 2 H₂O(g) [C] 2 H₂(g) + 4 OH⁻(aq) ⟶ 4 H₂O(g) + 4 e⁻ [D] O₂(g) + 2 H₂O(g) + 4 e⁻ ⟶ 4 OH⁻(aq)

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Video Transcript

Which of the following equations shows the reaction at the cathode of a hydrogen fuel cell under alkaline conditions? (A) Two H2 gas forms four H+ aqueous plus four e−. (B) O2 gas plus four H+ aqueous plus four e− forms two H2O gas. (C) Two H2 gas plus four OH− aqueous forms four H2O gas plus four e−. (D) O2 gas plus two H2O gas plus four e− forms four OH− aqueous.

The focus of our question is the hydrogen fuel cell. To better understand the series of reactions that take place within a hydrogen fuel cell, it is helpful to understand the structure of the cell and how electrons flow within it. Within our hydrogen fuel cell, both the anode and the cathode are hollow containers that are lined with a porous carbon.

The electrolyte solution can be an aqueous alkaline solution of potassium hydroxide or an acidic solution of sulfuric acid. As we can see, the incoming hydrogen and oxygen are both able to pass through the porous anodes and cathodes, respectively, and react with the electrolyte to form electrons. These reactions are what give galvanic cells their power. Galvanic cells rely on redox reactions and the flow of electrons they produce to power devices. Electrons will leave the anode, flow through the circuit, and arrive at the cathode.

In the case of our hydrogen fuel cell, hydrogen gas is oxidized and oxygen gas is reduced. At the anode, with a solution of potassium hydroxide, KOH, hydrogen gas feeds into the system. It loses electrons forming hydrogen ions that react with the hydroxide ions in the electrolyte. This, in turn, forms water molecules. At the cathode, oxygen gas is reduced by the water and electrons produced by the previous reaction to form hydroxide ions. The combination of the two half-equations can be represented as two H2 gas plus O2 gas forms two H2O gas.

Our question asks about the reaction that occurs at the cathode of a hydrogen fuel cell. As we can see, the reaction at the cathode can best be represented by O2 gas plus two H2O gas plus four e− forms four OH− aqueous. And therefore, answer choice (D) is correct.

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