Question Video: Modelling Real-World Objects Using Mathematical Solids | Nagwa Question Video: Modelling Real-World Objects Using Mathematical Solids | Nagwa

Question Video: Modelling Real-World Objects Using Mathematical Solids Mathematics

By modeling the trunk of the tree as a cylinder and the head of the tree as a sphere, ignoring any air between the leaves and branches, work out an estimate for the volume of the tree seen in the figure. Give your answer in terms of 𝜋.

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Video Transcript

By modeling the trunk of the tree as a cylinder and the head of the tree as a sphere, ignoring any air between the leaves and branches, work out an estimate for the volume of the tree seen in the given figure. Give your answer in terms of 𝜋.

In this question, we’re working out an estimate for the volume of the tree because in reality it won’t be a perfect sphere and a perfect cylinder, but these are reasonable models. We need to recall two key formulae. Firstly, the volume of a sphere is calculated using the formula four-thirds 𝜋𝑟 cubed, where 𝑟 is the radius of the sphere. And secondly, the volume of a cylinder is 𝜋𝑟 squared ℎ, where 𝑟 is the radius of the circular base and ℎ is the height of the cylinder.

Let’s consider the volume of the leaves first of all, which we’re modeling as a sphere. From the diagram, we can see that the diameter of this sphere is nine feet. The radius will be half of this. So, the radius of this sphere is 4.5 or nine over two feet. We have then that the volume of the leaves modeled as a sphere is four-thirds multiplied by 𝜋 multiplied by nine over two cubed. To cube nine over two, we can cube the numerator and denominator separately. Nine cubed is 729 and two cubed is eight. We can then cancel a factor of four from the numerator and denominator and also a factor of three, which leaves 243 over two 𝜋. Notice that the question asked us to give our answer in terms of 𝜋, so we won’t evaluate this.

Next, we consider the volume of the tree trunk, which we’re modeling as a cylinder. We can see that the height of the cylinder is eight feet and the diameter of its base is 1.5 feet. If we write this as a fraction, it’s three over two. And so, the radius will be half of this. We can double the denominator to give a radius of three over four feet. The volume of the trunk is, therefore, estimated as 𝜋 multiplied by three-quarters squared multiplied by eight.

Again, we can square the numerator and denominator of our fraction separately to give nine over 16. And then, we can cancel a factor of eight from the numerator and denominator to give nine 𝜋 over two as the volume of the tree trunk. The total volume of the tree then can be found by adding these two values together, 243 over two 𝜋 plus nine over two 𝜋. 243 over two plus nine over two is 252 over two. And 252 divided by two is 126. So, by modeling this tree as a composite solid composed of a cylinder and a sphere, we found an estimate for the total volume of the tree to be 126𝜋 cubic feet.

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