Question Video: Finding the Area of an Isosceles Triangle given Its Vertices’ Coordinates | Nagwa Question Video: Finding the Area of an Isosceles Triangle given Its Vertices’ Coordinates | Nagwa

Question Video: Finding the Area of an Isosceles Triangle given Its Vertices’ Coordinates

Given that 𝐴𝐵𝐶 is an isosceles triangle, where the coordinates of the points 𝐴, 𝐵, and 𝐶 are (8, −2), (−2, −2), and (0, −8), find the area of △𝐴𝐵𝐶.

02:46

Video Transcript

Given that 𝐴𝐵𝐶 is an isosceles triangle, where the coordinates of the points 𝐴, 𝐵, and 𝐶 are eight, negative two; negative two, negative two; and zero, negative eight. Find the area of triangle 𝐴𝐵𝐶.

So to help us understand what’s going on in this question, I’ve drawn a sketch. So I’ve got the points 𝐴, 𝐵, and 𝐶. And I’ve joined them to make a triangle. And I’ve also shown that the triangle is an isosceles triangle. And so I have marked that on. And we can see that because as we’re told that it’s an isosceles triangle and we can clearly see that the line 𝐵𝐶 is shorter than the other two, then the other two lines must be the same because, as we know, it’s an isosceles triangle.

So now to solve the problem, what we’re gonna do is work out the area of the triangle. And to do that we have a formula. And that formula states that the area of a triangle is equal to half the base times the height where the height is the perpendicular height. And what we mean by perpendicular height is the height at right angles to the base.

So the first thing we need to do to work out the area of the triangle is work out the length of our base, so 𝐵. 𝐵 is gonna be equal to eight, because that’s the 𝑥-coordinate of point 𝐴, minus negative two, because that’s the 𝑥-coordinate of point 𝐵, which is gonna give us a result of 10. And that’s because if you subtract a negative it’s the same as add. So eight add two is 10. And if we think about a number line if we’re counting up from negative two to eight, we count up 10 steps. So this is correct. So great, that’s our length of our base.

So now, what we want to do is work our perpendicular height ℎ. And to do this, this is gonna be equal to negative two minus negative eight. And that’s because we’ve got negative two because that’s the point at which 𝐴𝐵 crosses the 𝑦-axis. And then we subtract from this negative eight. And that’s because negative eight is the 𝑦-coordinate of point 𝐶. Again, when you subtract a negative it’s positive. So you have negative two add eight which gives a six. And again, if we think about if we’re counting down from negative two to negative eight, it would be six spaces or six units. So that’s correct.

So we’ve got our 𝐵 and our ℎ. So now, let’s find the area of our triangle. So, therefore, the area of the triangle 𝐴𝐵𝐶 is gonna be equal to a half multiplied by 10 multiplied by six. And we can work this out by thinking, what is half of 10? Well, it’s five. Five multiplied by six is 30. So, therefore, we can say that the area of the triangle 𝐴𝐵𝐶⁠ ⁠— given that the coordinates of the points 𝐴, 𝐵, and 𝐶 are eight, negative two; negative two, negative two; and zero, negative eight ⁠— is 30 units squared. And that’s our area.

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