Question Video: Using Binomial Expansion to Solve Exponential Equations | Nagwa Question Video: Using Binomial Expansion to Solve Exponential Equations | Nagwa

Question Video: Using Binomial Expansion to Solve Exponential Equations Mathematics • Third Year of Secondary School

Consider the expansion of ((𝑥⁵/8) −( 8/𝑥))⁹ in descending powers of 𝑥. For which values of 𝑥 is the sum of the middle two terms equal to zero?

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Video Transcript

Consider the expansion of 𝑥 to the fifth power over eight minus eight over 𝑥 all raised to the ninth power in descending powers of 𝑥. For which values of 𝑥 is the sum of the middle two terms equal to zero?

In this question, we have a binomial expression written in the form 𝑎 plus 𝑏 raised to the power of 𝑛. When expanding any expression of this type, we know it will have 𝑛 plus one terms. This means that our expansion will have 10 terms, and the middle two are the fifth and the sixth. We’re interested in 𝑎 sub five and 𝑎 sub six, the fifth and sixth terms of the expansion.

We know the general term of any binomial expansion 𝑎 sub 𝑟 plus one is equal to 𝑛 choose 𝑟 multiplied by 𝑎 to the power of 𝑛 minus 𝑟 multiplied but 𝑏 to the power of 𝑟. The fifth term is therefore equal to nine choose four multiplied by 𝑥 to the fifth power over eight to the fifth power multiplied by negative eight over 𝑥 to the fourth power.

The sixth term, on the other hand, is equal to nine choose five multiplied by 𝑥 to the fifth power over eight to the fourth power multiplied by negative eight over 𝑥 to the fifth power. We are told that the sum of these two terms is equal to zero. This means that the fifth term is equal to the negative of the sixth term. We notice that nine choose four is equal to nine choose five as they are both equal to nine factorial divided by five factorial multiplied by four factorial.

We can therefore cancel this on both sides of our equation. Both sides of the equation also can be divided by 𝑥 to the fifth power over eight raised to the fourth power. This means that the left-hand side becomes 𝑥 to the fifth power over eight. We can also divide both sides by negative eight over 𝑥 to the fourth power. The right-hand side becomes negative negative eight over 𝑥. The two negatives become a positive.

We can then cross multiply. We can multiply both sides by eight and 𝑥. This gives us 𝑥 to the sixth power is equal to 64. We can then take the sixth root of both sides. This gives us 𝑥 is equal to positive or negative two as positive and negative two both raised to the power of six give us 64.

The word “values” in the question suggests we will have more than one answer. The sum of the middle two terms is equal to zero when 𝑥 is equal to negative two or two.

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