Question Video: Calculating the Velocity of a Wire in a Magnetic Field | Nagwa Question Video: Calculating the Velocity of a Wire in a Magnetic Field | Nagwa

Question Video: Calculating the Velocity of a Wire in a Magnetic Field Physics • Third Year of Secondary School

A wire of length 120 cm moves perpendicularly to a magnetic flux of density 0.6 T. If the wire experiences an emf between its ends of 2 V, then the wire is moving with a velocity of _ m/s.

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Video Transcript

Fill in the blank. A wire of length 120 centimeters moves perpendicularly to a magnetic flux of density 0.6 teslas. If the wire experiences an emf between its ends of two volts, then the wire is moving with a velocity of blank meters per second. Is it (A) 0.03, (B) 0.36, (C) 1.44, or (D) 2.78?

Before we start solving this problem, it’s worth noting that in this context we can take magnetic flux density, which we measure in teslas as usual, to mean the same thing as magnetic field strength. Also, we’ll assume that the magnetic field in question is uniform. So let’s draw a diagram to help visualize this.

We don’t know the precise direction of the magnetic field, so let’s just choose to draw it pointing from left to right. We do know that the length of wire is moving in a direction perpendicular to the magnetic field. So let’s choose to draw it moving downwards, noting that its direction of motion makes a right angle with the direction of the magnetic field.

At this point, we should recall that for a straight conductor moving through a uniform magnetic field, an electromotive force, or emf, of magnitude 𝑙𝑣𝐵 sin 𝜃 is induced across it, where 𝑙 is the length of the conductor. 𝑣 is its velocity. 𝐵 is the magnetic field. And 𝜃 is the angle between the velocity and the magnetic field.

We’ve been asked for the velocity of the wire, so let’s rearrange this equation to make 𝑣 the subject. To do this, we can divide both sides of the equation by 𝑙, 𝐵, and sin 𝜃. So those terms cancel out of the right-hand side, leaving 𝑣 by itself. Thus, the expression can be written as the velocity equals the induced emf divided by 𝑙𝐵 sin 𝜃.

Next, we should make sure that all of our known values have the appropriate SI or SI-derived units. The emf is given as two volts, so it’s good to go, and so is the magnetic flux density written as 0.6 teslas. And of course, 𝜃 is just expressed in angular units. And here, 𝜃 equals 90 degrees. The only units that need to be converted are centimeters for the length of the wire, which should be written in plain meters. We know that one centimeter is one hundredth of a meter, so 120 centimeters is equal to 1.20 meters.

Finally, we can substitute all these values into the equation for velocity. Since all the values on the right-hand side are expressed in appropriate units, we know that this formula will give us a velocity value in the proper units of meters per second.

Now, entering this into our calculator, we get a result of 2.777 and so on meters per second. And choosing to round to two decimal places, this becomes 2.78 meters per second. This corresponds to answer option (D), which is the correct answer. A wire of length 120 centimeters moves perpendicularly to a magnetic flux of density 0.6 teslas. If the wire experiences an emf between its ends of two volts, then the wire is moving with a velocity of 2.78 meters per second.

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