Question Video: Simplfying an Algebraic Expression Using Exponent Laws | Nagwa Question Video: Simplfying an Algebraic Expression Using Exponent Laws | Nagwa

Question Video: Simplfying an Algebraic Expression Using Exponent Laws Mathematics • First Year of Preparatory School

Simplify ((−(𝑥/𝑦))⁻³)/((−(𝑥/𝑦))¹⁰).

03:19

Video Transcript

Simplify negative 𝑥 over 𝑦 all raised to the power of negative three all over negative 𝑥 over 𝑦 all raised to the 10th power.

In this question, we are asked to simplify an expression involving the quotient of two bases raised to different exponents. The first thing we want to notice is that the base in both expressions are the same. Remember that the base is the part of the expression that is being raised to a power. We can then note that this expression is in the same form as the quotient rule for exponents. This tells us that 𝑏 to the power of 𝑚 over 𝑏 to the power of 𝑛 is equal to 𝑏 to the power of 𝑚 minus 𝑛. We raise the base to the power of the difference of the exponents.

We can directly apply this rule to simplify the expression. Our base 𝑏 is negative 𝑥 over 𝑦, our value of 𝑚 is negative three, and our value of 𝑛 is 10. We obtain negative 𝑥 over 𝑦 all raised to the power of negative three minus 10. We can then evaluate the expression in the exponent to obtain negative 𝑥 over 𝑦 to the power of negative 13.

We could stop here. However, it is worth noting that there are many ways we can simplify this expression. For instance, we can recall that raising a base to a negative exponent is the same as raising the reciprocal of the base to the positive exponent. So we have that 𝑎 over 𝑏 all raised to the power of negative 𝑛 is equal to 𝑏 over 𝑎 all raised to the power of 𝑛.

We can use this to rewrite our answer. The reciprocal of the base is negative 𝑦 over 𝑥, and we need to raise this base to the power of positive 13. We can rewrite this one more time by recalling that raising a fraction to an exponent is the same as raising both the numerator and denominator to that exponent separately. So, 𝑏 over 𝑎 all raised to the power of 𝑛 is equal to 𝑏 to the power of 𝑛 over 𝑎 to the power of 𝑛. Applying this result with a numerator of negative 𝑦 gives us negative 𝑦 to the 13th power over 𝑥 to the 13th power.

We could even rewrite this further by noting that raising a negative number to an odd exponent is the same as raising the positive base to the exponent and multiplying by negative one. However, since there are so many ways of rewriting this expression, we will leave our answer as negative 𝑥 over 𝑦 all raised to the power of negative 13.

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