Question Video: Finding the Correct Change in an Atom Interacting with Two Identical Electrons | Nagwa Question Video: Finding the Correct Change in an Atom Interacting with Two Identical Electrons | Nagwa

Question Video: Finding the Correct Change in an Atom Interacting with Two Identical Electrons Physics • Third Year of Secondary School

The diagram shows an atom that interacts with two identical photons in a time interval shorter than the lifetime of the excited state of an electron in the atom. Which of the following more correctly shows the changes that have occurred just after the interaction between the atom and the second photon? [A] Diagram A [B] Diagram B [C] Diagram C [D] Diagram D [E] Diagram E

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Video Transcript

The diagram below shows an atom that interacts with two identical photons in a time interval shorter than the lifetime of the excited state of an electron in the atom. Which of the following more correctly shows the changes that have occurred just after the interaction between the atom and the second photon?

So, what this question and all of its answers are showing us are three distinct time intervals in which different interactions are occurring or not yet occurring as in the case of 𝑡 zero, which is before the photons interact with the atom at all. Then, at 𝑡 one, we see that the first photon has been absorbed into the lone electron, causing the electron to become excited and transition to a higher energy level. And after this, we have 𝑡 two, which occurs right after the second photon interacts with the atom, with the exact interaction being one of these five answers. So let’s look at them starting with (A).

(A) shows us the atom with the electron still in the excited state and no photons anywhere, which implies that this second photon was absorbed into this already excited electron. But for some reason, the electron stayed in the same energy state and releasing no photons. Because of this, we know that (A) cannot be correct. This second photon is interacting and something is occurring, that something being stimulated emission. When an already excited electron interacts with a photon, like we see here at 𝑡 one, the electron can actually transition down in energy level, releasing a photon with the same energy and same direction as the photon that initially caused this stimulation by interacting with the excited electron. So, since answer (A) does none of these things, we know it can’t be correct. So let’s see if this occurs in answer (B).

Since we don’t see any photons in answer (B), a stimulated emission couldn’t have occurred. What appears to have happened instead is that this second photon was absorbed into this already excited electron, causing it to become even more excited and transition up to an even higher energy level. This process is very much possible. Very energetic photons can transition already excited electrons up an energy level, maybe even several at a time. But this particular transition cannot occur in this case because this electron is interacting with two photons that are identical, meaning that they have the same energy.

When this first photon is absorbed at 𝑡 zero, it causes the electron to jump up from the first energy level, which we’ll call 𝐸 one, to the second energy level, which we’ll call 𝐸 two. And now, what’s happening in diagram (B) is that the already excited electron in 𝐸 two absorbs the second photon, causing a transition upwards to the third energy level, which we’ll call 𝐸 three. This is the general process that’s occurring, but it’s not something that can actually happen in reality because these two photons here have identical energies.

And so if the first photon has enough energy to send the electron from the first to the second energy level, then the second photon must also have that energy. But higher energy levels have higher differences in energy, which means it would take more energy to go from 𝐸 two to 𝐸 three, then from 𝐸 one to 𝐸 two. So, the second photon actually won’t be energetic enough to cause a transition upwards for this electron to the third energy level, which means that (B) is not the correct answer here since the second photon does not have a higher energy than the first photon.

So, let’s now turn our attention to answer (C). At first glance, answer (C) appears to be showing us a stimulated emission. The second photon stimulates an already excited electron, causing the electron to emit a photon with the same direction and energy as the incident photon, which also travels alongside it, since in stimulated emissions, the incident photon that stimulates the excited electron is not absorbed. However, this diagram actually is not showing us a correct stimulated emission because this excited electron has a transition downwards in order to emit this photon. So, because (C) doesn’t show the electron in the lower energy level, it can’t be correct. But if we look at diagram (E), we see that it does show the electron and the lower energy level.

An excited electron interacts with a photon, causing it to transition down in energy level and emit a photon with the same energy and same direction as the incident photon. This is what we expect to occur in a stimulated emission. So answer (E) shows us a stimulated emission. But how do we actually know that this is what’s going to occur here? Well, it has to do with what’s said in the first sentence. The photon interactions are occurring at a time interval shorter than the lifetime of the excited state of an electron in the atom. This means that between 𝑡 zero and 𝑡 one, there is no time for the electron that was excited by the first photon to transition downwards. If this were the case, we would see something like what occurs in diagram (D), which is an example of spontaneous emission.

Spontaneous emission occurs when an excited electron transitions to a lower energy level by itself, releasing a photon, which has the same energy as the photon that initially excited the electron but a different direction. Spontaneous emission occurs spontaneously. Physical systems in general tend towards the lowest stable energies. So, when there’s an electron in an excited state, if there is a lower energy state available, then it will decay downwards to it, releasing a photon in the process. But it still takes time for this transition downwards to occur usually on time scales of 10 to the power of negative eight seconds.

So, although spontaneous emission occurs very quickly, if two photons are able to interact with this same electron with a time interval shorter than the lifetime of the excited state of an electron, then it means that a stimulated emission will occur instead since there isn’t enough time for the excited electron to transition downwards before this second photon comes in and causes a stimulated emission.

Therefore, the process that most correctly shows the changes that have occurred just after the interaction between the atom and this second photon would be stimulated emission, which is shown correctly in diagram (E).

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