Question Video: Identifying Outliers in a Dot Plot | Nagwa Question Video: Identifying Outliers in a Dot Plot | Nagwa

Question Video: Identifying Outliers in a Dot Plot Mathematics

Which of the statements is correct for the distribution represented by the diagram? [A] The distribution is symmetric. [B] The distribution has an outlier at 6. [C] The distribution has a gap from 21 to 29. [D] The distribution has a cluster from 7 to 20. [E] the distribution has a peak at 22.

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Video Transcript

Which of the statements is correct for the distribution represented by the diagram? (A) The distribution is symmetric. (B) The distribution has an outlier at six. (C) The distribution has a gap from 21 to 29. (D) The distribution has a cluster from seven to 20. Or (E) the distribution has a peak at 22.

To find which of these is correct, we’ll consider them one at a time. First, the distribution is symmetric. To find out if this distribution is symmetric, you can sketch a line over the distribution. This image is not symmetric. The six is stretching out the image. And so, we can’t say that the distribution is symmetric.

Now, let’s consider statement (B) the distribution has an outlier at six. To consider a six as an outlier, we want to look at the spread of the data points. All of the other data points fall between 21 and 29. The distance from 6 to 21 is 15. We can say that the data point six is quite far removed from the rest of the data. And therefore, it is a true statement to say that this distribution has an outlier at six. But we want to go ahead and check the other three statements.

The distribution has a gap from 21 to 29. Since the majority of the points fall between 21 and 29, there is no gap there. Option (D) the distribution has a cluster from seven to 20. There are, in fact, no data points from seven to 20, which means there can’t be a cluster there. And finally, option (E) the distribution has a peak at 22. If we look closely at 22, there’s only one data point there. Looking across our diagram, we see that the peak happens at 26, which means option (E) is not correct, leaving us with only one true statement. The distribution has an outlier at six.

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