### Video Transcript

Given that the matrix negative
four, three, π₯, negative seven is equal to the matrix negative four, three, eight,
π¦ minus six, find the values of π₯ and π¦.

The question gives us two matrices
which we are told are equal. We need to use this information to
find the values of π₯ and π¦. Remember, for two matrices to be
equal, entries in the same row and column must be identical. So, for example, we must have both
entries in the first row and first column equal. In this case, theyβre both equal to
negative four. But this doesnβt really help us
find the values of π₯ or π¦. However, what happens if we look at
the values in row two column one? Remember, these must be equal. In our first matrix, the value in
row two column one is π₯. And in our second matrix, the value
in row two column one is eight. So for our matrices to be equal,
these two entries must be equal. In other words, we must have π₯ is
equal to eight.

Weβll want to do something similar
to help us find the value of π¦. We can see the only place π¦
appears is in our second matrix in row two column two. And for these two matrices to be
equal, they must have the same value in row two column two. So we can just equate the entries
in row two column two for both of these matrices. In other words, we must have
negative seven is equal to π¦ minus six. And we can then just solve this
equation for π¦. Weβll add six to both sides of the
equation. And we see that this gives us that
π¦ is equal to negative one.

One thing thatβs often worth doing
in situations like this is substituting our value of π¦ back into our matrix. Remember, when we do this, we
should get the entry of negative seven. So weβll substitute π¦ is negative
one into the expression in row two column two in our second matrix. This gives us negative one minus
six. And we can evaluate this, and we
get negative seven just as we expected. This just helps us check that our
answer was correct. Therefore, given the matrix
negative four, three, π₯, negative seven is equal to the matrix negative four,
three, eight, π¦ minus six, we were able to show that the value of π₯ must be eight
and the value of π¦ must be negative one.