Video Transcript
What are the π₯-intercept and
π¦-intercept of the line three π₯ plus two π¦ minus 12 equals zero?
We begin by recalling that the
π₯-intercept is the point at which our graph crosses the π₯-axis. And this means that the
π¦-coordinate must be equal to zero. Likewise, the π¦-intercept is the
point at which the graph crosses the π¦-axis. And at this point, the
π₯-coordinate equals zero. This can be represented on the
π₯π¦-coordinate plane as shown. The π₯-intercept has coordinates
π, zero and the π¦-intercept coordinates zero, π. It is these values of π and π
that we are trying to calculate in this question.
Substituting π₯ equals π and π¦
equals zero into our equation, we have three multiplied by π plus two multiplied by
zero minus 12 equals zero. The left-hand side simplifies to
three π minus 12. We can then add 12 to both sides
such that three π is equal to 12. And dividing through by three gives
us π is equal to four. The point at which the line
intersects the π₯-axis is four, zero. And as such, the π₯-intercept is
four.
Substituting π₯ equals zero and π¦
equals π into our equation, we have three multiplied by zero plus two multiplied by
π minus 12 equals zero. This simplifies to two π minus 12
equals zero. Adding 12 to both sides and then
dividing through by two, we have π is equal to six. The graph passes through the
π¦-axis at the point zero, six. And we can therefore conclude that
the π¦-intercept is six. The π₯- and π¦-intercepts of the
line three π₯ plus two π¦ minus 12 equals zero are four and six, respectively.