### Video Transcript

By applying the relation π choose
π plus π choose π minus one equals π plus one choose π, deduce the value of 59
choose two plus 59 choose three.

This is called the recursive
relationship. And it can help us to simplify
expressions. In this case, weβre looking to
deduce the value of 59 choose two plus 59 choose three. So letβs compare this expression
with the recursive relationship. In this relation, we see that on
the left-hand side, we have two terms with the same value of π. We have 59 choose two and 59 choose
three. So weβre going to let π be equal
to 59. Then we have π and π minus
one. The first term has a larger value
of π. And the second term has a value of
π thatβs one less.

So letβs imagine weβre going to
swap 59 choose three and 59 choose two around so that it matches this criteria. Then we see π must be equal to
three. π minus one is three minus one,
which is two, as we require. According to the relation given in
the question then, 59 choose three plus 59 choose two must be equal to π plus one,
so 59 plus one choose three. Thatβs 60 choose three. So to deduce the value of the
expression in our question, we need to work out what 60 choose three is.

And so we recall that π choose π
is π factorial over π factorial times π minus π factorial. Now, we mustnβt confuse π and π
with the values we defined earlier. This time, π is going to be equal
to 60, and π is still equal to three. This gives us that 60 choose three
is 60 factorial over three factorial times 60 minus three factorial or 60 factorial
over three factorial times 57 factorial. Now, we could use our calculator to
evaluate this, but letβs look at how the definition of the factorial can help us
simplify a little.

π factorial is π times π minus
one times π minus two all the way down to one. This means 60 factorial is 60 times
59 times 58 and so on. But of course, we see that we can
actually rewrite that further as 60 times 59 times 58 times 57 factorial. This means our expression for 60
choose three can be rewritten as shown. And this is great because we can
now divide through by a constant factor of 57 factorial. In fact, three factorial is equal
to six, so we can also divide our numerator and denominator by six. And we see that 60 choose three is
10 times 59 times 58 over one. 59 multiplied by 58 is 3,422. So 10 times 59 times 58 is
34,220. 59 choose two plus 59 choose three
is, therefore, 34,220.