If a coin is flipped and then a dice is thrown, what is the probability of the coin landing on heads and the die landing on number three?
We recall that the probability of an event occurring can be written as a fraction. The number of successful outcomes is the numerator. And the number of possible outcomes is the denominator.
When flipping a coin, there are two possible outcomes, heads or tails. In this question, we need the probability of the coin landing on heads. This is equal to one-half or one out of two. A fair die is cubic and has numbers one to six on each of its faces. This means that there are six possible outcomes. The probability of landing on number three is one out of six or one-sixth.
We need to calculate the probability that both of these events occur. The coin needs to land on heads and the die needs to land on three. When dealing with probability, the word “and” means multiply. We need to multiply the fractions one-half and one-sixth. Multiplying the numerators gives us one, and multiplying the denominators gives us 12. This means that the probability of the coin landing on heads and the die landing on number three is one-twelfth or one out of 12.