### Video Transcript

Suppose that π of π₯ is equal to
π₯ squared plus ππ₯ plus π all over π₯ squared minus seven π₯ plus four. Given that π of zero is equal to
one and π prime of zero is equal to four, find π and π.

Our first step in this question can
be to substitute π₯ equals zero into π of π₯. Since weβre given that π of zero
is equal to one. We obtain that π of zero is equal
to zero squared plus π times zero plus π all over zero squared minus seven times
zero plus four. Now, all of these terms will go to
zero apart from π and four. Weβre left with π of zero is equal
to π over four. Next, we use the fact that the
question has told us that π of zero is equal to one. And so, we can set this equal to
one. From this, we find that π is equal
to four. Next, we can use the fact that π
prime of zero is equal to four. However, first of all, we must find
π prime of π₯. In order to do this, we need to
differentiate π. Since π is a rational function, we
can use the quotient rule in order to find its derivative.

The quotient rule tells us that π’
over π£ prime is equal to π£ times π’ prime minus π’ times π£ prime all over π£
squared. Setting our function π of π₯ equal
to π’ over π£, we obtain that π’ is equal to π₯ squared plus ππ₯ plus π. And π£ is equal to π₯ squared minus
seven π₯ plus four. We can find π’ prime and π£ prime
by differentiating these two functions. Giving us that π’ prime is equal to
two π₯ plus π and π£ prime is equal to two π₯ minus seven. Now, we can substitute these into
the quotient rule. We obtain that π prime of π₯ is
equal to π₯ squared minus seven π₯ plus four multiplied by two π₯ plus π minus π₯
squared plus ππ₯ plus π multiplied by two π₯ minus seven all over π₯ squared minus
seven π₯ plus four all squared.

Now, we could simplify π prime of
π₯ at this point. However, weβre going to be
substituting in π₯ is equal to zero. And so, a lot of these terms would
just disappear. Letβs simply substitute π₯ equals
zero in here. We obtain this. However, a lot of the terms will
vanish to zero, which leaves us with four π plus seven π all over 16. Now, we have found that π is equal
to four earlier. And so, we can substitute this in,
giving us four π plus 28 all over 16.

Since the question has told us that
π prime of zero is equal to four, we can set this equal to four. Then, we simply rearrange this in
order to solve for π. Now, we obtain our solution that π
is equal to nine. Weβve now found the values of both
π and π, which completes the solution to this question.