Question Video: Rationalizing Covalent Bonding in Oxygen | Nagwa Question Video: Rationalizing Covalent Bonding in Oxygen | Nagwa

Question Video: Rationalizing Covalent Bonding in Oxygen Chemistry • 7th Grade

Oxygen forms a diatomic molecule with a double covalent bond. The structural formula for diatomic oxygen is shown. Why do oxygen atoms in this molecule form more than 1 covalent bond? [A] There are 6 valence electrons in the oxygen atom, so 2 electrons must be shared between atoms to produce stable octets in their outer shells. [B] There are two valence electrons in the oxygen atom, so sharing 4 electrons between atoms fully utilizes their outer shells. [C] There are 6 valence electrons in the oxygen atom, so 4 electrons must be shared between atoms to produce stable octets in their outer shells. [D] There are 2 valence electrons in the oxygen atom, so sharing 2 electrons between atoms fully utilizes their outer shells. [E] There are 4 valence electrons in the oxygen atom, so 4 electrons must be shared between atoms to produce stable octets in their outer shells. Which of the following elements also commonly forms a diatomic molecule with more than one covalent bond? [A] Be [B] Ne [C] C [D] N [E] F

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Video Transcript

Oxygen forms a diatomic molecule with a double covalent bond. The structural formula for diatomic oxygen is shown. Why do oxygen atoms in this molecule form more than one covalent bond? (A) There are six valence electrons in the oxygen atom, so two electrons must be shared between atoms to produce stable octets in their outer shells. (B) There are two valence electrons in the oxygen atom, so sharing four electrons between atoms fully utilizes their outer shells. (C) There are six valence electrons in the oxygen atom, so four electrons must be shared between atoms to produce stable octets in their outer shells. (D) There are two valence electrons in the oxygen atom, so sharing two electrons between atoms fully utilizes their outer shells. (E) There are four valence electrons in the oxygen atom, so four electrons must be shared between atoms to produce stable octets in their outer shells.

The first portion in all of our answer choices has to do with the number of valence electrons in the oxygen atom. Oxygen has six valence electrons. So we can rule out answer choices (B), (D), and (E). The next portion of our two remaining answer choices has to do with the number of electrons that are shared between atoms. Let’s get these incorrect answer choices out of the way before we think about this part of the problem.

The valence shell of oxygen, as well as many other atoms, holds a maximum of eight electrons. Eight valence electrons, or a full octet, is a very stable electron configuration. It’s the same electron configuration as a noble gas, such as neon. As this electron configuration is so stable, atoms have a tendency to transfer or share electrons so that they can have a full valence shell. This is known as the octet rule. In an oxygen molecule, electrons are shared to create a covalent bond. By doing this, both oxygen atoms can have a full octet.

Both oxygen atoms in the oxygen molecule are two electrons away from a full octet. So, if both oxygen atoms share two electrons, both atoms will end up with a full octet. This means that there are four electrons being shared in total. Two electrons are needed to create one covalent bond. So, the four electrons shared by the oxygen atom will create two covalent bonds.

So, the reason oxygen atoms in the oxygen molecule form more than one covalent bond is answer choice (C): there are six valence electrons in the oxygen atom, so four electrons must be shared between atoms to produce stable octets in their outer shells.

Which of the following elements also commonly forms a diatomic molecule with more than one covalent bond? (A) Be, (B) Ne, (C) C, (D) N, (E) F.

As we saw in the last part of the problem, atoms form covalent bonds so that they can share electrons to fill the valence shell. So, let’s figure out how many valence electrons each of our answer choices have. Beryllium has two valence electrons, neon has eight, carbon has four valence electrons, nitrogen has five, and atoms of fluorine have seven.

We can see that neon already has a full valence shell, so it won’t form any covalent bonds. This is not the correct answer. Beryllium is an element in group two of the periodic table. Beryllium can form some compounds with covalent bonding such as beryllium hydride. But for the most part, beryllium forms compounds with ionic bonds like the other elements in group two. So, answer choice (A) is also not correct. This leaves us with answer choices (C), (D), and (E).

Atoms of carbon need four more electrons to have a full valence shell. So, carbon atoms tend to form four covalent bonds. This is why carbon forms compounds like methane and carbon dioxide. But we’re specifically interested in diatomic molecules in this question. In order for there to be a diatomic carbon molecule, there would have to be four bonds between the carbon atoms. But a quadruple bond is not something that exists. So, answer choice (C) is not correct.

Atoms of nitrogen have five valence electrons. So, atoms of nitrogen tend to form three bonds to have a full valence shell. This means there can be a diatomic nitrogen molecule with three bonds between the nitrogen atoms. So, nitrogen is an element that can form a diatomic molecule with more than one covalent bond. So answer choice (D) is the correct answer, but let’s take a quick peek at answer choice (E).

Atoms of fluorine have seven valence electrons, so these atoms can form one bond. So atoms of fluorine do tend to form diatomic molecules, but this diatomic molecule only has one covalent bond, not more than one. So, answer choice (E) is incorrect.

Of the elements that we were given, the only one that forms a diatomic molecule with more than one covalent bond was answer choice (D) nitrogen.

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