### Video Transcript

Find the value of the determinant
of matrix π΄: π₯, negative 11, π₯, negative one.

The determinant of a matrix is
denoted by absolute value bars, and the determinant of any two-by-two matrix of the
form π, π, π, π is equal to ππ minus ππ. This means that the determinant of
the matrix π₯, negative 11, π₯, negative one is equal to π₯ multiplied by negative
one minus negative 11 multiplied by π₯. Multiplying the top-left and
bottom-right value gives us negative π₯. Multiplying the top-right and
bottom-left value gives us negative 11π₯. We need to subtract this from
negative π₯. This can be simplified to negative
π₯ plus 11π₯. The determinant of matrix π΄: π₯,
negative 11, π₯, negative one is therefore equal to 10π₯.