### Video Transcript

Determine the variation function π
of β for π of π₯ is equal to negative π₯ squared plus ππ₯ plus 17 at π₯ is equal
to negative one. Additionally, find π if π of four
over nine is 11 over six.

Weβre given the function π of π₯
is negative π₯ squared plus ππ₯ plus 17 and asked to find the variation function
for this at π₯ is negative one. To do this, we recall that for a
function π of π₯ at π₯ is equal to πΌ, the variation function π of β is π of πΌ
plus β minus π of πΌ, where β is the change in π₯ from π₯ is equal to πΌ. Once we found our function π of β,
weβll then substitute β is four over nine to find the value of π in our function
π. So weβre given π of π₯ is negative
π₯ squared plus ππ₯ plus 17. With π₯ is negative one, this is
equal to our πΌ. And substituting πΌ is negative
one, we have π of β is π of negative one plus β minus π of negative one.

And now evaluating our function π
at π₯ is equal to negative one plus β, we have negative negative one plus β squared
plus π times negative one plus β plus 17. That is, π of negative one plus β
is equal to negative one minus two β plus β squared minus π plus πβ plus 17. And multiplying our parentheses by
negative one and collecting like terms, we have negative β squared plus β times π
plus two plus 16 minus π. Now, evaluating π at π₯ is equal
to negative one, we have negative negative one squared plus π times negative one
plus 17, that is, negative one minus π plus 17, which is 16 minus π. And substituting our two results
into our function π of β, we see that 16 minus π minus 16 minus π is equal to
zero so that π of β is equal to negative β squared plus β times π plus two.

Our variation function for π of π₯
is equal to negative π₯ squared plus ππ₯ plus 17 at π₯ is negative one is equal to
π of β is negative β squared plus β times π plus two. Now weβre given that π of four
over nine is equal to 11 over six. And this means that if we
substitute β is equal to four over nine into π of β, this should equal 11 over
six. And this means that negative four
over nine squared plus four over nine times π plus two is 11 over six. And weβre going to use this to find
the value of π. Evaluating this gives us negative
16 over 81 plus four π over nine plus eight over nine is equal to 11 over six. And now if we add 16 over 81 and
subtract eight over nine from both sides and multiplying both sides by nine over
four, we can isolate π on the left-hand side.

Canceling through our parentheses,
we then have π is equal to 33 over eight plus four over nine minus two, which
evaluates to 2.5694 and so on. So with our variation function π
of β is negative β squared plus β times π plus two, we have a value of π equal to
2.57 to two decimal places.