Video Transcript
Find the equation of the line that
passes through the points π΄ negative 10, two and π΅ zero, five, giving your answer
in the form ππ₯ plus ππ¦ plus π is equal to zero.
Weβve been given the coordinates of
two points that lie on the straight line. The form in which weβre asked to
give the equation, ππ₯ plus ππ¦ plus π equals zero, is the general form of the
equation of a straight line. This is called the general equation
of a straight line because the equation of every straight line can be written in
this form. The values of π, π, or π may be
zero. But itβs still possible to write
every straight line in this form whether itβs a diagonal line, a horizontal line, or
a vertical line.
To begin this problem though, weβre
going to use the slopeβintercept form of the equation of a straight line: π¦ equals
ππ₯ plus π, where π gives the slope of the line and the value of π is its
π¦-intercept. We should be aware that the value
of π here isnβt the same as the value of π in the general form. These are the letters commonly used
though, so weβll stick with them for now. But we need to be aware that they
arenβt the same.
Now, we know that this line passes
through the point π΅, which has coordinates zero, five, In other words, when π₯ is
equal to zero, π¦ is equal to five. As this point has an π₯-coordinate
of zero, it lies on the π¦-axis. And so we know that the
π¦-intercept of the line is five.
We therefore determine the value of
one of the two unknowns π and π. And we know that the equation of
this line in slopeβintercept form at the moment is of the form π¦ equals ππ₯ plus
five. To find the value of π, we need to
calculate the slope of the line. We recall that the slope of a line
is its change in π¦ over its change in π₯. And if we have the coordinates of
two points π₯ one, π¦ one and π₯ two, π¦ two that lie on the line, the slope can be
calculated using the formula π equals π¦ two minus π¦ one over π₯ two minus π₯
one.
If we allow π΄ to be the point π₯
one, π¦ one and π΅ to be the point π₯ two, π¦ two, we can substitute these values
into the slope formula. We have five minus two in the
numerator and zero minus negative 10 in the denominator. We need to be especially careful
here because a common mistake would be to simply write zero minus 10. Evaluating gives three in the
numerator and positive 10 in the denominator. So the slope of the line is
three-tenths. We can therefore substitute this
value of π into the slopeβintercept form of the equation of the line. And we have π¦ equals three-tenths
of π₯ plus five.
Now, this is the equation of the
line passing through the points π΄ and π΅. But it isnβt in the form in which
weβve been asked to give our answer. In the general form, we can see
that the three terms, the π₯-term, the π¦-term, and the constant term, are all on
the same side of the equation. Although it doesnβt specify this,
the values of π, π, and π in this general form are usually integers. So we also need to deal with the
fact that we have a fraction of three-tenths.
Weβll begin then by multiplying
every term in our equation by 10. And it gives 10π¦ is equal to three
π₯ plus 50. We then want to group all of the
terms on the same side of the equation, which we can do by subtracting both three π₯
and 50 from each side, giving negative three π₯ plus 10π¦ minus 50 is equal to
zero. This is now in the general form of
the equation of a straight line. We can see that the value of π,
the coefficient of π₯, is negative three. The value of π, which is the
coefficient of π¦, is positive 10. And the value of π, the constant
term, is negative 50. So we have our answer.
Itβs also worth pointing out that
we couldβve chosen to group the terms on the other side of the equation. By subtracting 10π¦ from each side,
weβd have the equation three π₯ minus 10π¦ plus 50 is equal to zero, which is the
exact negative of the equation weβve already found. These equations are equivalent as
they can be obtained from the other by multiplying through by negative one. Our answer then, the equation of
the line that passes through the points π΄ and π΅ in its general form, is negative
three π₯ plus 10π¦ minus 50 equals zero.