Question Video: Finding the Dimensions of a Rectangular Piece of Land | Nagwa Question Video: Finding the Dimensions of a Rectangular Piece of Land | Nagwa

Question Video: Finding the Dimensions of a Rectangular Piece of Land Mathematics • First Year of Preparatory School

The length of a rectangular piece of land is 1 meter longer than two times the width. The perimeter is 150 meters. Find the dimensions of this rectangular piece of land.

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Video Transcript

The length of a rectangular piece of land is one meter longer than two times the width. The perimeter is 150 meters. Find the dimensions of this rectangular piece of land.

In this question, we are asked to find the dimensions of a rectangular piece of land. To do this, we are told that the perimeter of the land is 150 meters and that the length of the rectangle is one meter longer than two times the width.

To answer this question, let’s start by sketching the rectangular piece of land. We can say that it has a length of 𝑙 meters and a width of 𝑤 meters. We are told in the question that the length of the rectangle is one meter longer than twice the width. This means that if we double the width and add one meter, we will have an expression equal to the length of the land. Therefore, 𝑙 is equal to two 𝑤 plus one.

We can also recall that the perimeter of a polygon is the sum of its side lengths. So the perimeter of a rectangle is twice its length plus twice its width. Since we are told that the perimeter is 150 meters, we must have 150 equals two 𝑙 plus two 𝑤. We can construct an equation involving only 𝑤 by substituting the expression for 𝑙 into the perimeter equation. Substituting 𝑙 equals two 𝑤 plus one into the equation gives us 150 is equal to two times two 𝑤 plus one plus two 𝑤.

We now have an equation in terms of 𝑤 that we want to solve for 𝑤. To do this, we need to isolate 𝑤 on one side of the equation. We can start by distributing the factor of two over the parentheses. Doubling each term inside the parentheses gives us that 150 is equal to four 𝑤 plus two plus two 𝑤. We can simplify the right-hand side of the equation by collecting the like terms. We have four 𝑤 plus two 𝑤 equals six 𝑤. We can now solve for 𝑤 by isolating 𝑤 on the right-hand side of the equation. We subtract two from both sides of the equation. This gives us 148 is equal to six 𝑤.

We can then divide both sides of the equation by six to obtain that 𝑤 is equal to 148 over six. We can simplify this fraction by dividing both the numerator and denominator by two. This gives us that the width of the rectangular piece of land is 74 over three meters. We can find the length of the land by recalling that it is twice the width plus one meter. Substituting 𝑤 equals 74 over three into the equation and calculating gives us that 𝑙 is equal to 151 over three.

Hence, the width of the rectangular piece of land is 74 over three meters, and the length is 151 over three meters.

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