# Video: Solving Rational Equations in a Real-Life Context

Liam went on a bike ride of 48 miles. He realized that if he had gone 4 mph faster, then he would have arrived 6 hours sooner. How fast did he actually ride?

07:22

### Video Transcript

Liam went on a bike ride of 48 miles. He realized that if he had gone four miles per hour faster, then he would have arrived six hours sooner. How fast did he actually ride?

We know that distance equals speed multiplied by time which means we have data from Liamโs actual bike ride, his distance, time, and speed. And then we have some information about an increased speed ride, the distance, time, and speed. Letโs fill in what we know about the actual bike ride. The distance was 48 miles. We donโt know how long it took. So we can just call the time ๐ก. We also donโt know the speed of his actual bike ride. Letโs call that value ๐ . On Liamโs increased speed ride, the distance would be the same, 48 miles. And the time would be Liamโs first time minus six hours. So we can use the variable ๐ก and then subtract six.

Weโll follow a similar approach when it comes to the speed of the increased ride. Itโs his original speed plus four miles per hour. Weโre interested in how fast he actually was riding. Thatโs our ๐ก variable. Because we know that distance equals speed multiplied by time, we can also say that time is equal to the distance divided by the speed. In the actual bike ride, ๐ก is equal to 48 divided by ๐ . And in the increased speed ride, we have the original time minus six is equal to the same distance 48 over ๐  plus four. We know that ๐ก equals 48 over ๐ .

So weโll take information from our first equation, what we know that ๐ก equals, and plug it into our second equation. And weโll have something that looks like this. 48 over ๐  minus six equals 48 over ๐  plus four. To subtract six from 48 over ๐ , we need a common denominator. We can multiply six by ๐  over ๐ , which gives us six ๐  over ๐ . And that means we can subtract 48 minus six ๐  and put it all over ๐ . And that is equal to 48 over ๐  plus four.

Now, we really want to solve for ๐ . And to do that, weโll need to get ๐  by itself. There is an ๐  in three places in this equation. So we need to start by eliminating these fractions. And weโll do that by cross-multiplying. 48 minus six ๐  times ๐  plus four will be equal to ๐  times 48, 48๐ . We need to multiply ๐  plus four times 48 minus six ๐ . And that means we need to foil ๐  times 48 equals 48๐ , ๐  times negative six ๐  equals negative six ๐  squared, four times 48 equals 192, and four times negative six ๐  equals negative 24๐ , all equal to 48๐ .

We can combine our two like terms, 48๐  minus 24๐  equals 24๐ . And weโll have negative six ๐  squared plus 24๐  plus 192 is equal to 48๐ . We wanna set this equation equal to zero. And we can do that by subtracting 48๐  from that side. And if we subtract from the right side, we need to subtract from the left side. 24๐  minus 48๐  equals negative 24๐ .

Now, we have an equation equal to zero. But we also have a negative leading coefficient. When weโre factoring, we never want a negative leading coefficient. We can solve this problem by multiplying the whole equation by negative one. Negative one times negative six ๐  squared equals six ๐  squared. Negative one times negative 24๐  positive 24๐ , and negative one times 192 is negative 192. And the zero doesnโt change.

The next thing we notice is that this entire equation is divisible by six. We can divide every term by six. And we now have this. ๐  squared plus four ๐  minus 32 equals zero. We want to factor this equation. And that means we need two factors of negative 32 that when added together equal positive four. One and negative 32 will be far too big, two and negative 16 when added together equal negative 14. Weโre getting closer, but weโre still not there. Four and negative eight when added together equal negative four. Weโre almost there. If we use negative four and positive eight, they add together to equal positive four.

The missing terms are then negative four and positive eight. ๐  minus four times ๐  plus eight equal zero. We have to set ๐  minus four equal to zero. And then set ๐  plus eight equal to zero to solve for ๐ . Add four to both sides and ๐  will equal four. Subtract eight from both sides and ๐  will equal negative eight. But our ๐  value represents a speed. And speed cannot be negative. We know that ๐  equals negative eight is not a valid option. And that means that ๐  must be equal to four. And ๐  in our key is equal to the speed of the actual bike ride. And that would be four miles per hour.

Actual speed equals four miles per hour. If we plug that in to our first equation, we find that the time it took Liam would be equal to 48 divided by four, 12 hours. We could plug in what we know to find out how quickly he would have completed the race, if he increased his speed. 12 minus six equals six hours. If Liam increased his speed from four miles per hour to eight miles per hour, he would have completed the 48 miles in six hours. However, the only piece of information this question was actually looking for is this one. Liamโs actual speed was four miles per hour.