Question Video: Deducing the Chemical Formula of a Hydrocarbon Undergoing Cracking | Nagwa Question Video: Deducing the Chemical Formula of a Hydrocarbon Undergoing Cracking | Nagwa

Question Video: Deducing the Chemical Formula of a Hydrocarbon Undergoing Cracking Chemistry • Third Year of Secondary School

An unidentified hydrocarbon is cracked. It produces two product molecules. One of these molecules has the chemical formula C₁₀H₂₂. The other one has the formula C₂H₄. What is the formula of the unidentified hydrocarbon? [A] C₁₁H₂₂ [B] C₁₁H₂₄ [C] C₁₂H₂₄ [D] C₁₂H₂₆ [E] C₁₃H₂₈

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Video Transcript

An unidentified hydrocarbon is cracked. It produces two product molecules. One of these molecules has the chemical formula C10H22. The other one has the formula C2H4. What is the formula of the unidentified hydrocarbon? (A) C11H22, (B) C11H24, (C) C12H24, (D) C12H26, or (E) C13H28.

The hydrocarbon whose formula we’re trying to determine has undergone a cracking reaction. A cracking reaction is a type of decomposition reaction where larger organic molecules are broken down into smaller molecules. Typically, overall when a larger hydrocarbon is cracked, carbon-to-carbon bonds are broken so that smaller organic molecules can be produced. The cracking reaction in the question resulted in two products: C10H22 and C2H4.

We know that C10H22 is an alkane, as it fits the general formula of alkanes of C𝑛H2𝑛+2, where 𝑛 in this case is equal to 10. We also know that C2H4 is an alkene, as it fits the general formula of alkenes, which is C𝑛H2𝑛, where in this case 𝑛 is equal to two. Let’s use the chemical formulas of the products to deduce the chemical formula of the unidentified hydrocarbon.

In a cracking reaction, just as we would expect in any chemical reaction, the total number of each type of atom present in the reactants must be equal to the total number of each type of atom present in the products. We can calculate the total number of carbon and hydrogen atoms present after the cracking reaction occurred to find the number of carbon and hydrogen atoms originally present in the unidentified hydrocarbon. The total number of carbon atoms in the products would be 10 plus two, which gives us a total of 12. The total number of hydrogen atoms in the products would be 22 plus four, which gives us 26. So there must be 12 carbon atoms and 26 hydrogen atoms in the reactants.

Since there is only one reactant molecule in this cracking reaction, we can use these values as the subscripts in the chemical formula, which gives us C12H26. Therefore, the unidentified hydrocarbon that underwent the cracking reaction has the chemical formula in answer choice (D), C12H26.

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