Video: Addition of Two Algebraic Expressions

Simplify (8π‘₯Β² βˆ’ 3π‘₯ + 2) + (3π‘₯Β² + 5π‘₯ + 1).

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Video Transcript

Simplify eight π‘₯ squared minus three π‘₯ plus two plus three π‘₯ squared plus five π‘₯ plus one.

As we’re just adding the two parts of the expression, we can remove the brackets or parentheses. Once we have done this, we can group or collect the like terms. We need to group the π‘₯ squared terms. We also group the π‘₯ terms. And finally, we’ll group the constants.

The π‘₯ squared terms are eight π‘₯ squared and three π‘₯ squared. Eight plus three is equal to 11. Therefore, eight π‘₯ squared plus three π‘₯ squared equals 11 π‘₯ squared. It is important to remember that the exponents or power will not change when adding and subtracting. The first term in our simplified expression is 11 π‘₯ squared. The two π‘₯ terms are negative three π‘₯ and positive five π‘₯. Negative three plus five is equal to two. Therefore, negative three π‘₯ plus five π‘₯ equals two π‘₯. The second term of our simplified expression is two π‘₯.

Finally, we need to group the constants, positive two and positive one. Two plus one is equal to three. Therefore, our final term is positive three.

The expression eight π‘₯ squared minus three π‘₯ plus two plus three π‘₯ squared plus five π‘₯ plus one simplifies to 11 π‘₯ squared plus two π‘₯ plus three.

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