Question Video: Determining the Function of a Translated Graph | Nagwa Question Video: Determining the Function of a Translated Graph | Nagwa

Question Video: Determining the Function of a Translated Graph Mathematics

The graph of the function 𝑓, 𝑦 = 𝑓(π‘₯), is translated four units in the positive 𝑦-direction. Write, in terms of 𝑓(π‘₯), the equation of the translated graph.

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Video Transcript

The graph of the function 𝑓, 𝑦 is equal to 𝑓 of π‘₯ is translated four units in the positive 𝑦-direction. Write, in terms of 𝑓 of π‘₯, the equation of the translated graph.

We’re told that the graph 𝑦 is equal to 𝑓 of π‘₯ of the function 𝑓 is translated four units in the positive 𝑦-direction. So let’s see how this looks with respect to a particular graph. Suppose, for example, our function looks like the one shown. Now, if this function is translated four units in the positive 𝑦-direction, this means that the whole function is moved up by four units. But what does this mean with respect to our function 𝑦 is equal to 𝑓 of π‘₯?

Well, to see what’s happening, we can look at some specific points. And for convenience, we choose points where both the input and output are whole numbers. So, for example, when π‘₯ is negative two, 𝑦 equals 𝑓 of π‘₯ is positive two. When π‘₯ is negative one, 𝑦 is negative one. When π‘₯ is zero, 𝑦 is negative two. And when π‘₯ is one, 𝑦 is negative one. And π‘₯ is two; 𝑦 is also two. But now what about our new function, the translated function, which we’ll call 𝑔 of π‘₯?

When π‘₯ is negative two in this case, 𝑔 of π‘₯ is positive six. When π‘₯ is negative one, 𝑔 of π‘₯ is positive three. When π‘₯ is zero, 𝑔 of π‘₯ is positive two. When π‘₯ is one, 𝑔 of π‘₯ is three. And when π‘₯ is two, 𝑔 of π‘₯ is six. So let’s compare these values with our outputs for 𝑓 of π‘₯. So, when π‘₯ is negative two, we see that 𝑔 of π‘₯ is six, which is two plus four, and that’s equal to 𝑓 of negative two plus four. And similarly, when π‘₯ is negative one, we see that 𝑔 of negative one is 𝑓 of negative one plus four. That’s minus one plus four. When π‘₯ is zero, 𝑔 of zero is two, which is equal to negative two plus four, and that’s 𝑓 of zero plus four. And when π‘₯ is one, 𝑔 of one is three, which is negative one plus four, and that’s 𝑓 of one plus four. And finally, when π‘₯ is equal to two, 𝑔 of two is equal to two plus four. That’s 𝑓 of two plus four, which is six.

So we see that in every case, 𝑔 of π‘₯ is equal to the value of 𝑓 of π‘₯ plus four. That is, for all of our π‘₯-values, the outcome after the translation by four units in the positive 𝑦-direction is 𝑦 is equal to 𝑓 of π‘₯ plus four. And this is the equation of the translated graph.

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