Video Transcript
According to Cramerβs rule and given that β³ sub π₯ is equal to the determinant of the two-by-two matrix three, seven, five, two and β³ sub π¦ is equal to the determinant of the two-by-two matrix negative five, three, negative two, five, write the simultaneous equations of the system.
In this question, weβre given expressions for β³ sub π₯ and β³ sub π¦ in accordance with Cramerβs rule. We need to use these expressions to determine the simultaneous equations of the system represented by these two expressions. And to do this, we start by noting weβre given expressions for β³ sub π₯ and β³ sub π¦. And these are given as two-by-two matrices. This means our system will only have two unknowns, π₯ and π¦.
So letβs recall Cramerβs rule for two unknowns. This tells us if we have two simultaneous equations ππ₯ plus ππ¦ is equal to π and ππ₯ plus ππ¦ is equal to π and the determinant of the matrix of coefficients is nonzero β thatβs β³ is equal to the determinant of the matrix π, π, π, π β then π₯ is equal to β³ sub π₯ divided by β³ and π¦ is equal to β³ sub π¦ divided by β³ is the unique solution to the system of linear equations.
Well, itβs worth noting β³ sub π₯ is the determinant of the matrix π, π, π, π and β³π¦ is the determinant of the matrix π, π, π, π. So to find an expression for β³ sub π₯, we take our expression for β³ and replace the first column in the expression for β³, which is the coefficients of π₯ in our simultaneous equations, with the constants of the simultaneous equations. Thatβs π, π.
So to find the simultaneous equations, we need to determine the values of π, π, π, π, π, and π. And we can do this by using the given expressions for β³ sub π₯ and β³ sub π¦. First, using β³ sub π₯, we can determine the values of π, π, π, and π. We have π is equal to three, π is equal to seven, π is equal to five, and π is equal to two. And we can then follow the same process for our expression for β³ sub π¦. This gives us that π is equal to negative five, π is equal to three, π is equal to negative two, and π is equal to five.
And now we can just substitute these values into our simultaneous equations, which then gives us our final answer. The system of simultaneous equations given by Cramerβs rule for β³ sub π₯ and β³ sub π¦ given in the question is negative five π₯ plus seven π¦ is equal to three and negative two π₯ plus two π¦ is equal to five.