### Video Transcript

By completing the square, find the center and radius of the circle π₯ squared minus four π₯ plus π¦ squared minus four π¦ minus eight equals zero.

The equation of a circle is π₯ minus β squared plus π¦ minus π squared equals π squared. β, π is the center point, and π is the radius, the length. So we will be completing the square because thatβs the standard equation that the formula is in.

So we want to somehow go from π₯ squared minus four π₯ to something squared in terms of π₯, and the same thing for π¦, and then have a constant on the right-hand side of the equation that will be our radius. So to complete the square, we will take our π term which is the negative four β itβs the coefficient in front of the π₯ term β and we will take π, divide by two, and square it.

So when we take negative four divided by two, thatβs negative two, and when we square it, thatβs positive four. So letβs do the exact same steps for the π¦s. Now notice our π term that weβll divide by two and then square is actually the exact same as for the π₯; theyβre both negative four, so we can add the exact same number for the π¦.

And then to move the negative eight over to the right, we add eight to both sides, so itβs equal to eight. So again, the whole point of completing the square is to end up with something squared, π₯ squared minus four π₯ plus four, that is, π₯ minus two squared, which is the same thing as π₯ minus two times π₯ minus two.

We could always FOIL that back and you would still get π₯ squared minus four π₯ plus four. And since itβs the same expression for π¦, itβs the same thing, π¦ minus two squared. Now, however, the right-hand side of the equation is not eight.

Notice how we added two fours to the left-hand side of the equation. You have to keep equations balanced. So if you added them to one side of the equation, youβre going to have to add them to the other side of the equation, so this will actually be equal to not eight, but 16.

So this will be the equation of our circle. Both of these equations are equal; theyβre just in different forms. And the equation of a circle is in this form because itβs useful when youβre trying to find the center. So, for example, this center of this equation would be two, two because two is β and two is the same as π, in our equation. And then itβs equal to π squared.

So if we just wanted the radius, we would have to square-root π squared to find π, so the square root of 16 would mean the radius is four, but again, our equation would be π₯ minus two squared plus π¦ minus two squared equals 16.