Question Video: Determining the Current Gain of a Transistor Circuit | Nagwa Question Video: Determining the Current Gain of a Transistor Circuit | Nagwa

Question Video: Determining the Current Gain of a Transistor Circuit Physics • Third Year of Secondary School

Which of the following is a correct equivalent formula for 𝛽_𝑒 in terms of 𝛼_𝑒? [A] 𝛼_(𝑒)/(1 − 𝛼_(𝑒)) [B] 1/𝛼_(𝑒) [C] 𝛼_(𝑒)/(1 + 𝛼_(𝑒)) [D] 1 − (1/𝛼_(𝑒))

03:12

Video Transcript

Which of the following is a correct equivalent formula for 𝛽 sub 𝑒 in terms of 𝛼 sub 𝑒? (A) 𝛼 sub 𝑒 divided by one minus 𝛼 sub 𝑒. (B) One divided by 𝛼 sub 𝑒. (C) 𝛼 sub 𝑒 divided by one plus 𝛼 sub 𝑒. (D) One minus one over 𝛼 sub 𝑒.

In this question, we are being asked about the quantities 𝛼 sub 𝑒 and 𝛽 sub 𝑒, which are terms describing current gain in a transistor. Let’s recall that a transistor is an electric component made of a collector, a base, and an emitter. Current through these parts is labeled 𝐼 sub 𝐶, 𝐼 sub 𝐵, and 𝐼 sub 𝐸, respectively. These currents relate to one another via the equations 𝐼 sub 𝐸 equals 𝐼 sub 𝐶 plus 𝐼 sub 𝐵 and 𝐼 sub 𝐶 equals 𝐼 sub 𝐸 times 𝛼 sub 𝑒. The first equation relates the magnitudes of the currents. The second equation relates the collector and emitter currents to the constant of proportionality 𝛼 sub 𝑒.

Now, we are being asked here to relate 𝛼 sub 𝑒 to 𝛽 sub 𝑒, so let’s recall how 𝛽 sub 𝑒 is defined. 𝛽 sub 𝑒 is the ratio of the collector current to the base current, 𝐼 sub 𝐶 over 𝐼 sub 𝐵. Our approach to solving this question will be to rearrange and combine these two equations to get expressions for 𝐼 sub 𝐶 and 𝐼 sub 𝐵 involving the quantity 𝛼 sub 𝑒 that we can then substitute into this equation. We’ll begin by taking this first equation and subtracting 𝐼 sub 𝐶 from both sides, which gives us an expression for 𝐼 sub 𝐵 in terms of 𝐼 sub 𝐸 and 𝐼 sub 𝐶.

We can now use this second equation to substitute 𝐼 sub 𝐸 times 𝛼 sub 𝑒 in place of 𝐼 sub 𝐶 in this equation. We then have that 𝐼 sub 𝐵 is equal to 𝐼 sub 𝐸 minus 𝐼 sub 𝐸 times 𝛼 sub 𝑒. We can now factor out the 𝐼 sub 𝐸 that appears in both terms on the right-hand side, giving us the equation 𝐼 sub 𝐵 is equal to 𝐼 sub 𝐸 multiplied by one minus 𝛼 sub 𝑒. We now have this equation which relates 𝐼 sub 𝐵 to 𝛼 sub 𝑒 and 𝐼 sub 𝐸, in addition to this equation relating 𝐼 sub 𝐶 to the same two quantities 𝛼 sub 𝑒 and 𝐼 sub 𝐸.

We can now use these two equations in order to substitute for 𝐼 sub 𝐶 and 𝐼 sub 𝐵 in this equation for 𝛽 sub 𝑒. Let’s clear some space on screen to do this. Subbing in our expressions for 𝐼 sub 𝐶 and 𝐼 sub 𝐵 into our equation for 𝛽 sub 𝑒, we find that 𝛽 sub 𝑒 is equal to 𝐼 sub 𝐸 times 𝛼 sub 𝑒 divided by 𝐼 sub 𝐸 times one minus 𝛼 sub 𝑒. We can notice that there’s an 𝐼 sub 𝐸 term in the numerator and denominator of this expression, which will cancel each other out. This leaves us with an expression for 𝛽 sub 𝑒 in terms of 𝛼 sub 𝑒, which is what we were asked to find.

We have that 𝛽 sub 𝑒 is equal to 𝛼 sub 𝑒 divided by one minus 𝛼 sub 𝑒. This matches the expression given in answer choice (A). And so we can identify option (A) as being the correct answer. 𝛽 sub 𝑒 is equal to 𝛼 sub 𝑒 divided by one minus 𝛼 sub 𝑒.

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