### Video Transcript

The position of a particle is given by position as a function of time equals 4.0π‘ squared
in the π direction minus 3.0 in the π direction plus 2.0π‘ cubed in the π direction
meters. What is the velocity of the particle at 0.0 seconds? What is the velocity of the
particle at 1.0 seconds? What is the average velocity of the particle between 0.0 seconds and
1.0 seconds?

Letβs call the velocity of the particle at 0.0 seconds π£ of 0.0 s and the velocity of the
particle at 1.0 seconds π£ of 1.0 s. And weβll call the average velocity of the particle
between 0.0 and 1.0 seconds π£ sub avg.

Solving for these values will involve taking a time derivative of the position of the
particle function. So letβs begin on that now.

We can recall that the velocity of a particle π£ is equal to the time derivative of the
position of the particle. Applying this relationship to our scenario, the velocity of the
particle as a function of time is equal to the time derivative of π of π‘.

We take that derivative term by term. The derivative of the πth component of π is 8.0 times
π‘; the derivative of the πth component of π is zero; and the derivative of the πth
component of π is 6.0 times π‘ squared.

And because weβve differentiated with respect to time, instead of units of meters we now have
units of meters per second. We can now move ahead with solving for the velocity at 0.0
seconds.

When we plug in zero for π‘, all components of velocity go to zero, so the velocity at 0.0
seconds equals zero meters per second.

Now we can move onto solving for velocity when time equals 1.0 seconds. When we plug in 1.0
seconds for π‘, then our velocity equals 8.0π plus 6.0π meters per second.

Now weβre ready to move onto solving for π£ sub avg. The particleβs average speed between 0.0
seconds and 1.0 seconds, that average speed is equal to the position of the particle at 1.0
seconds minus the position of the particle at 0.0 seconds divided by change in time which
works out to 1.0 seconds.

If we plug in 1.0 seconds for π‘ in the π of π‘ equation, then we find thatβs equal to 4.0π minus 3.0π plus 2.0π.

Then when we evaluate that function at time π‘ equals 0.0 seconds, it equals simply minus 3.0π.

Since weβre subtracting that term in the first place, it becomes positive 3.0π. Looking at
the numerator of this fraction, we see that the π component cancels out so that our final
answer for the average speed of the particle over this time interval is 4.0π plus 2.0π
meters per second.

This is the particleβs average velocity for the first second of its motion.