Question Video: Determining the Value of an Unknown by Finding the Composition of Two Linear Functions | Nagwa Question Video: Determining the Value of an Unknown by Finding the Composition of Two Linear Functions | Nagwa

# Question Video: Determining the Value of an Unknown by Finding the Composition of Two Linear Functions Mathematics

Given that π(π₯) = 3π₯ + 2, find π΅ so that π(π₯) = β3π₯ + π΅ satisfies π β π = π β π.

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### Video Transcript

Given that π of π₯ equals three π₯ plus two, find π΅ so that π of π₯ equals negative three π₯ plus π΅ satisfies π of π equals π of π.

Letβs take a moment to understand the notation being used in this question. We have two functions, π of π₯ and π of π₯. Weβre then given this equation here: π of π equals π of π. On the left-hand side, we have π of π, which means the composite function we get when we take an input, apply the function π, and then apply the function π to the result, whereas on the right-hand side we have π of π, which means the composite function we get when we take an input, apply the function π first, and then apply the function π to the result.

The order in which we apply these functions is really important because in general composition of functions is not commutative, by which we mean the order does matter. In this specific case of these two functions π and π, weβre told that π of π of π₯ is equal to π of π of π₯ for a particular value of this unknown π΅. And we need to work out what that value is. To do this, letβs find algebraic expressions for π of π and π of π of π₯.

Letβs start with π of π of π₯. When we take an input π₯ and apply the function π, we get negative three π₯ plus π΅. We then take this as the input to the function π. So, we have π of negative three π₯ plus π΅. Now, π is the function that takes an input, multiplies it by three, and then adds two. So, weβre going to replace the input π₯ with negative three π₯ plus π΅. So, we multiply negative three π₯ plus π΅ by three and then add two. Distributing the parentheses, we have that π of π of π₯ is equal to negative nine π₯ plus three π΅ plus two.

Now letβs see what happens when we compose the two functions in the other order. So, weβre going to take an input π₯, apply the function π, and then apply the function π. Applying the function π first gives three π₯ plus two. And then we take this as our input to the function π. We multiply this expression by negative three and add the unknown π΅. Distributing the parentheses, we have π of π of π₯ is equal to negative nine π₯ minus six plus π΅.

Now, we want these two expressions to be equal to each other for a particular value of π΅. So, we have negative nine π₯ plus three π΅ plus two equals negative nine π₯ minus six plus π΅. We can see straightaway that the π₯-terms cancel, leaving three π΅ plus two equals negative six plus π΅. Collecting all of the π΅s on the left-hand side of the equation by subtracting π΅ from each side gives two π΅ plus two equals negative six. Then, we subtract two from each side to give two π΅ equals negative eight and finally divide both sides of the equation by two to give π΅ equals negative four. We found then that the value of this unknown π΅ such that π of π of π₯ is equal to π of π of π₯ for all values of π₯ is negative four.

This question does also illustrate a general point, which is that when we compose two linear functions, such as those we have here, the coefficient of π₯ will be the same no matter which order we compose them in, in this case itβs equal to negative nine, whereas the constant term will in general be different.

We found that for the given functions π and π of π₯, the value of π΅ that satisfies π of π of π₯ equals π of π of π₯ is negative four.

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