Video Transcript
The figure shows the graph of π¦
equals π of π₯ and the point π΄. The point π΄ is a local
maximum. Identify the corresponding local
maximum for the transformation π¦ equals π of two π₯.
Letβs begin by recalling the
transformation that maps the graph of π¦ equals π of π₯ onto the graph of π¦ equals
π of two π₯. We know that for a function π¦
equals π of π₯, π¦ equals π of π times π₯ is a horizontal dilation by a scale
factor of one over π. And so, if we compare our equation,
thatβs π¦ equals π of two π₯, to the general equation, π¦ equals π of ππ₯, we can
see that weβre going to have a horizontal dilation. Letβs work the scale factor out by
letting π be equal to two.
When we do, we see that for our
function π¦ equals π of π₯, π¦ equals π of two π₯ is a horizontal dilation by a
scale factor of one-half. In other words, weβre going to
compress our graph about the π¦-axis. When we do, it looks a little
something like this. Weβll call the coordinate of our
local maximum on our transformation π΄ prime as shown. We can see that its π¦-coordinate
remains unchanged, but its π₯-coordinate is halved. So, π΄ prime is two over two, one
or one, one. And so, we see that the
corresponding local maximum for the transformation π¦ equals π of two π₯ is one,
one.