Question Video: Finding the Perimeter of a Figure in a Composite Figure | Nagwa Question Video: Finding the Perimeter of a Figure in a Composite Figure | Nagwa

Question Video: Finding the Perimeter of a Figure in a Composite Figure Mathematics

Two plots of land have the same area. One is a square, and the other is a rhombus with diagonals of lengths 48 m and 35 m. What is the perimeter of the square plot? Give your answer to two decimal places.

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Video Transcript

Two plots of land have the same area. One is a square, and the other is a rhombus with diagonals of lengths 48 meters and 35 meters. What is the perimeter of the square plot? Give your answer to two decimal places.

In this question, it might be helpful to draw some diagrams to visualize the problem. We’re told that there’s two plots of land, and one is a square, and the other is a rhombus. Let’s draw the square. We know that this will be a quadrilateral with four sides of the same length and all the interior angles will be 90 degrees. When it comes to the rhombus, we know that this will be a quadrilateral with all four sides the same length. On this diagram, we can put the double markation on the lines so that we don’t get confused into thinking the lengths of this rhombus will be the same as the lengths of the square.

The other information that we’re given is the lengths of the diagonals on the rhombus. The longer one is 48 meters, and the shorter one is 35 meters. We’re also told that these two plots of land, the square and the rhombus, have the same area. And we’re asked to find the perimeter of the square plot. We can remember that the perimeter of a shape is the distance around the outside. We could do this if we had the length of the side of the square, but we don’t; we’ll need to calculate it. Let’s see if we can find the area of the rhombus. To do this, we’ll need to recall a certain formula.

We can find the area of a rhombus using the two diagonals 𝑑 sub one and 𝑑 sub two by multiplying 𝑑 sub one and 𝑑 sub two and then dividing by two. We can simply plug in our two diagonals of 35 and 48 to work out 35 times 48 over two. It’s always good to simplify a calculation when we can. We’re asked to give our answer to two decimal places here, so we can assume that a calculator would be allowed.

Either by using a calculator or by a written method, we’ll get our answer of 840. And as it’s an area, our units will be square meters. We were told that the areas were the same, which means that the square will also have an area of 840 square meters. We’ll need to remember that the area of a square is equal to the length squared. And this time, we’re plugging in the fact that the area is 840. So, we have 840 is equal to 𝐿 squared. In order to find the value of 𝐿, we would take the square root of both sides of our equation. So, 𝐿 is equal to the square root of 840. As we’re dealing with a length, the units will be in meters.

It’s always tempting to pick up our calculator and find the decimal value for this. But as we still need to find the perimeter, we’ll keep our answer in the square root form. We remember that the perimeter of the square will be the distance around the outside edge, which means that we’ll be working out four multiplied by the square root of 840. Using our calculator, we get the decimal value of 115.93101 and so on meters. Rounding to two decimal places means we check our third decimal digit to see if it’s five or more. And as it isn’t, then our answer rounds down to give us the perimeter of the square is 115.93 meters.

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