Question Video: Finding the Perimeter of a Triangle Using the Triangle Midsegment Theorem and Triangle Congruence | Nagwa Question Video: Finding the Perimeter of a Triangle Using the Triangle Midsegment Theorem and Triangle Congruence | Nagwa

Question Video: Finding the Perimeter of a Triangle Using the Triangle Midsegment Theorem and Triangle Congruence Mathematics • Second Year of Preparatory School

Use the data in the figure to determine the length of line segment 𝐷𝐹 and then the perimeter of △𝐷𝐸𝐹.

04:48

Video Transcript

Use the data in the figure to determine the length of line segment 𝐷𝐹 and then the perimeter of triangle 𝐷𝐸𝐹.

Let’s begin this question then by looking at the data that we are given. We can observe that we have a congruent pair of line segments, 𝐴𝐹 and 𝐵𝐹. And there is another pair of congruent line segments, 𝐴𝐸 and 𝐶𝐸. We can also note that there is a right angle marked on the diagram. So the measure of angle 𝐴𝐷𝐶 is 90 degrees. This would also allow us to note that the measure of angle 𝐴𝐷𝐵 would also be 90 degrees, as 𝐵𝐶 is a straight line segment and the sum of the measures on a straight line is 180 degrees.

Now, the first length that we need to calculate is that of the line segment 𝐷𝐹. We can consider this line segment in the context of this triangle 𝐴𝐵𝐷, which is marked in pink. In this way, we can then see that line segment 𝐷𝐹 is a line segment from a vertex of this triangle to the midpoint of the opposite side. And that would indicate that line segment 𝐷𝐹 is a median of this triangle.

We can also note that triangle 𝐴𝐵𝐷 is a right triangle. This is important because it means we can apply the property that in a right triangle, the length of the median from the vertex of the right angle equals half the length of the triangle’s hypotenuse. As the median is drawn from the vertex of the right angle, then we can write that this median 𝐷𝐹 is half the length of the hypotenuse, which is the line segment 𝐴𝐵. From the diagram, we have that 𝐴𝐵 is 49 centimeters, and half of this would give 24.5 centimeters. And so we have found the first required length of line segment 𝐷𝐹.

Next, we need to find the perimeter of triangle 𝐷𝐸𝐹. And we can recall that the perimeter is the distance around the outside edge. We have the lengths of one of the sides, which is 𝐷𝐹. So, to work out the perimeter, we’ll need to find the lengths of line segments 𝐸𝐹 and 𝐸𝐷.

Let’s take the line segment 𝐸𝐷 first. Just as we saw before, the line segment 𝐸𝐷 forms a median of the right triangle 𝐴𝐶𝐷. And this median is from the vertex containing the right angle. That means that its length will be half the length of the hypotenuse of triangle 𝐴𝐶𝐷, which is the line segment 𝐴𝐶. We are given on the diagram that the length of 𝐴𝐶 is 45 centimeters. So line segment 𝐸𝐷 has a length of 22.5 centimeters.

Now, we need to find the final length in triangle 𝐷𝐸𝐹, which is the line segment 𝐸𝐹. This time, we can’t say that line segment 𝐸𝐹 is a median of any triangle. It is, however, a line segment joining the midpoints of two line segments. And that brings us to one of the triangle midsegment theorems, that the length of the line segment joining the midpoints of two sides of a triangle is equal to half the length of the third side. So the length of line segment 𝐸𝐹 is half the length of the third side, which is the line segment 𝐵𝐶. And given that 𝐵𝐶 is 37 centimeters, then half of this is 18.5 centimeters.

We now have enough information to work out the perimeter of triangle 𝐷𝐸𝐹. We can add the three side lengths of 24.5, 22.5, and 18.5 centimeters, which gives us an answer of 65.5 centimeters. So the answers to both parts of the question can be given as the length of line segment 𝐷𝐹 equals 24.5 centimeters and the perimeter of triangle 𝐷𝐸𝐹 is 65.5 centimeters.

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