Question Video: Interpreting Newton’s Third Law of Motion | Nagwa Question Video: Interpreting Newton’s Third Law of Motion | Nagwa

Question Video: Interpreting Newton’s Third Law of Motion Mathematics • Third Year of Secondary School

Fill in the blank with <, >, =, ≤, or ≥: When a body of mass m is suspended from a spring scale fixed at the ceiling of an elevator and the elevator descends with uniform acceleration, then the apparent weight _ the real weight.

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Video Transcript

Fill in the blank with less than, greater than, equal to, less than or equal to, or greater than or equal to. When a body of mass 𝑚 is suspended from a spring scale fixed at the ceiling of an elevator and the elevator descends with uniform acceleration, then the apparent weight what the real weight.

Let’s begin by thinking about what is actually happening here. We have a body suspended from a spring scale fixed to a ceiling. The reading on the scale gives the apparent weight. And we can think about this as the upward force in newtons. Then the real weight is the downward force of the mass of the body due to acceleration. That real weight is generally calculated by multiplying mass times gravity, 𝑚𝑔. Then we can calculate the net force by finding the sum in a given direction of the apparent weight and the real weight.

The direction in which we choose to find the sum is somewhat arbitrary, but it can be easier to think about the direction in which the object is accelerating. In this case, we’re told that the elevator is descending with uniform acceleration. So, we might define the downwards direction in this case to be positive. Then we can link all of these elements using Newton’s third law of motion: net force is equal to mass times acceleration. Since we define downwards to be positive, we can say here that the real weight minus the apparent weight is the net force. This is equal to mass times acceleration. So, if we define the acceleration to be 𝑎, this net force is equal to 𝑚𝑎.

But remember, the elevator is descending with uniform acceleration, so we can say that 𝑎 must be positive since we defined the downwards direction to be positive. Since mass, of course, is also positive, we can say that mass times acceleration must also be positive. It’s greater than zero. If 𝑚𝑎 is positive, then we can also say that the net force must also be greater than zero. In other words, the real weight minus the apparent weight must be greater than zero. We can rearrange this inequality by adding apparent weight to both sides. When we do, we get the following inequality. The real weight must be greater than the apparent weight. In other words, the apparent weight is going to be less than the real weight. And so, we can fill in the blank.

This means that when a body of mass 𝑚 is suspended from a spring scale fixed at the ceiling of an elevator and the elevator descends with uniform acceleration, then the apparent weight must be less than the real weight. We fill in the blank with the “less than” symbol.

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