Question Video: Finding the Additive Inverse of a Given Number Involving Exponents | Nagwa Question Video: Finding the Additive Inverse of a Given Number Involving Exponents | Nagwa

Question Video: Finding the Additive Inverse of a Given Number Involving Exponents Mathematics • First Year of Preparatory School

Find the additive inverse of the number (10/49) × (−7)².

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Video Transcript

Find the additive inverse of the number 10 over 49 times negative seven squared.

The first thing we should do is comment on what the additive inverse of a number is. The additive inverse of a number is what you would add to a number to create a sum of zero. In order to find out what the additive inverse of 10 over 49 times negative seven squared is, we should do some simplification.

We know that negative seven squared is 49. And that means the expression we have is 10 over 49 times 49. Since 49 has a one in the denominator, we can say that the 49 in the numerator and the 49 in the denominator cancel out, leaving us with 10 over one, or simply 10. This means we’re looking for the additive inverse of the number 10. What do we add to 10 to equal zero?

If you imagine 10 on a number line, to get to zero, you need to move to the left 10 times. That is, we need to subtract 10, go left 10 places. And so if we wanted to add something to 10 to equal zero, that value would be negative 10. 10 plus negative 10 equal zero. And the additive inverse of 10 over 49 times negative seven squared is equal to negative 10.

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