Question Video: Solving Clues with the Four Operations to Find a Pair of Numbers | Nagwa Question Video: Solving Clues with the Four Operations to Find a Pair of Numbers | Nagwa

Question Video: Solving Clues with the Four Operations to Find a Pair of Numbers Mathematics

I am thinking of two numbers. Use the clues to determine what the numbers are. (i) When you divide one by the other, the quotient is 8. (ii) The sum of the two numbers is 81.

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Video Transcript

I am thinking of two numbers. Use the clues to determine what the numbers are. When you divide one by the other, the quotient is eight. The sum of the two numbers is 81.

So in this problem, what we have are two variables because we’re told that we need to find two numbers. So therefore, what we’re gonna call these variables is 𝑥 and 𝑦. So now what we can do is set up a couple equations using our two clues. We’ll use the first clue. We’re told that if we divide one by the other, the quotient is eight. So therefore, we can set up our first equation which is 𝑥 divided by 𝑦 is equal to eight. And that’s because the quotient is the result of a division. And I’m gonna label this equation one cause this helps us as we go through our method.

Now, we can take a look at the second clue and set up an equation using this because we’re told that the sum of the two numbers is 81. So therefore, we have 𝑥 plus 𝑦 equals 81. And we’ve called this equation two. So now, what we’ve got is a pair of simultaneous equations. So what we’re gonna use to solve these simultaneous equations is a method called substitution. And to do this, we need to rearrange one of our equations so that 𝑥 or 𝑦 is the subject. Well, in fact, you could use either of the equations, but what we’re gonna use is equation one. And we could rearrange this by multiplying each side of the equation by eight. And when we do this, we’ve got 𝑥 as a subject to the equation cause 𝑥 is equal to eight 𝑦. And we’re gonna call this one equation three.

So as we said, we’re gonna be using the substitution method. So what we can do now as we’ve got 𝑥 as the subject is substitute equation three into equation two. As I said, we could’ve made 𝑥 or 𝑦 the subject and we could’ve rearranged either equation one or equation two. It’s just that we chose to do equation one. So now that we’ve substituted in equation three into equation two, we get eight 𝑦 plus 𝑦 equals 81, which is gonna give us nine 𝑦 is equal to 81. So then, we divide each side of the equation by nine and we get 𝑦 is equal to nine. So great! What we’ve done is we’ve found our first variable or, in fact, our first one of our two numbers.

So now to enable us to find our other variable 𝑥, what we’re gonna do is we substitute 𝑦 equals nine into one of our other equations. Well, in fact, the best one to substitute it into is equation three because we already got 𝑥 as the subject. And when we do this, what we get is 𝑥 is equal to eight multiplied by nine. So this’s gonna give us 𝑥 is equal to 72. So therefore, we can say that our values are gonna be 72 and nine.

And what we can do is we can double-check this by substituting them back into our original equations that we got from our clues. So if we look at our first clue or our first equation, we’re gonna have 72 divided by nine is equal to eight. Well, yes, this is correct because 72 divided by nine is eight. Well then for our second equation, we got 𝑥 plus 𝑦 equals 81. Well, we’ve got 72 plus nine equals 81. So again, this is correct. So therefore, yes, 72 and nine are our two numbers.

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