Question Video: Calculating Fluid Pressure at a Point from Point Depth and Fluid Density | Nagwa Question Video: Calculating Fluid Pressure at a Point from Point Depth and Fluid Density | Nagwa

Question Video: Calculating Fluid Pressure at a Point from Point Depth and Fluid Density Physics • Second Year of Secondary School

What is the pressure exerted by water at a depth of 2.5 m? Use a value of 1000 kg/m³ for the density of water.

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Video Transcript

What is the pressure exerted by water at a depth of 2.5 meters? Use a value of 1000 kilograms per cubic meter for the density of water.

So in this example, say that we have a column of water. And we’re interested in the pressure exerted by that water at a depth of 2.5 meters below the surface. So let’s say that’s a point here in our water column. The pressure at this point we’ve marked is created by the weight of all the water that’s above that point in our water column. And by the way, it doesn’t make a difference how wide the column is. However wide or narrow it is, the pressure will be the same as long as we have this certain depth, 2.5 meters.

To answer this question of what is the pressure exerted by the water at that point, we can recall that the pressure created by a fluid is equal to the density of that fluid multiplied by its height below the surface of the fluid times 𝑔, the acceleration due to gravity. Recalling that 𝑔 is 9.8 meters per second squared, when it comes to the density of our fluid, we’re given that in our problem statement, 1000 kilograms per cubic meter. And we’re also given the height, ℎ, 2.5 meters. And this means we can get right to calculating this pressure. It’s equal to the density of the water multiplied by the height below the surface of the water times the acceleration due to gravity.

Now before we multiply these numbers together, notice the units involved. That all the units are in base unit form. We see that in the numerator of our units, we have these two factors of 𝑚, the distance in meters. While in the denominator, we have meters cubed. This means if we were to multiply all the units involved together, we would get an overall result of kilograms per meter second squared. This is equivalent to a newton per meter squared. And we can recall that a newton per meter squared is equal to the unit pascal, which is a pressure unit. This means that the units we’ll end up with after we do our calculation are pascals. When we multiply these three numbers together, we find a result of 24500 pascals. That’s the pressure exerted by the water at this depth.

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