Question Video: Identifying the Vector Equation of a Line Passing through a Point with a Given Direction Vector | Nagwa Question Video: Identifying the Vector Equation of a Line Passing through a Point with a Given Direction Vector | Nagwa

Question Video: Identifying the Vector Equation of a Line Passing through a Point with a Given Direction Vector Mathematics • Third Year of Secondary School

Which of the following straight lines has a direction vector 〈4, 5, 1〉 and passes through the point 〈5, 3, 2〉? [A] 𝐫 = 〈5, 3, 2〉 + 𝑡〈4, 5, 1〉 [B] 𝐫 = 〈−5, −3, −2〉 + 𝑡〈4, 5, 1〉. [C] 𝐫 = 〈−5, −3, −2〉 + 𝑡〈−4, −5, 1〉 [D] 𝐫 = 〈5, 3, 2〉+ 𝑡〈−4, −5, 1〉 [E] 𝐫 = 〈4, 5, 1〉 + 𝑡〈5, 3, 2〉

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Video Transcript

Which of the following straight lines has a direction vector four, five, one and passes through the point five, three, two? Option (A) 𝐫 equals five, three, two plus 𝑡 times four, five, one. Option (B) 𝐫 equals negative five, negative three, negative two plus 𝑡 times four, five, one. Is it option (C) 𝐫 equals negative five, negative three, negative two plus 𝑡 times negative four, negative five, one? Option (D) 𝐫 equals five, three, two plus 𝑡 times negative four, negative five, one. Or is it option (E) 𝐫 equals four, five, one plus 𝑡 times five, three, two?

In this question, we are given five vector equations of lines and asked to determine which of these lines has a direction vector four, five, one and passes through the point five, three, two.

To answer this question, we can start by recalling that a direction vector of the line is any nonzero vector parallel to the line. We can also recall that a vector equation of a line is an equation of the form 𝐫 equals 𝐫 sub zero plus 𝑡 times 𝐝, where 𝐫 sub zero is the position vector of any point on the line and 𝐝 is any direction vector of the line.

Vector equations of a line are not unique, since we can choose any point on the line for the position vector 𝐫 sub zero and any direction vector of the line for 𝐝. For example, we could have 𝐝 as the vector four, five, one and 𝐫 sub zero as the vector five, three, two. This gives us that 𝐫 is equal to the vector five, three, two plus 𝑡 times the vector four, five, one, which we can see matches option (A).

For due diligence, we could check the remaining options to see if they are possible vector equations of the line. If we did this, we would find that options (C), (D), and (E) cannot be vector equations of the line since their direction vectors are not parallel to the given direction vector.

Showing that option (B) is not a possible vector equation of the line is more tricky. We would need to show that the point with coordinates negative five, negative three, negative two does not lie on the given line. We could do this by solving a vector equation; however, it is not necessary. Instead, we can conclude that the vector equation in option (A) has a direction vector of four, five, one and passes through the point five, three, two, so it is a vector equation of this straight line.

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