Question Video: Finding the Unknown Length in a Right Triangle Using Trigonometry Where the Unknown Is on the Bottom of the Fraction | Nagwa Question Video: Finding the Unknown Length in a Right Triangle Using Trigonometry Where the Unknown Is on the Bottom of the Fraction | Nagwa

Question Video: Finding the Unknown Length in a Right Triangle Using Trigonometry Where the Unknown Is on the Bottom of the Fraction Mathematics • Third Year of Preparatory School

Find 𝑥 to two decimal places.

03:01

Video Transcript

Find 𝑥 to two decimal places.

In this right triangle, we know the measure of one of the other angles and the length of one side. We want to calculate the length of another side of this triangle. We can do this using trigonometry. We’ll begin by labeling the three sides of this triangle in relation to the angle of 20 degrees. The side directly opposite the right angle is the hypotenuse of the triangle. The side opposite the angle of 20 degrees is the opposite. And the side between the right angle and the angle of 20 degrees is the adjacent.

Next, we recall the acronym SOHCAHTOA to help us decide whether we need the sine, cosine, or tangent ratio in this question. The side we know is the opposite. And the side we want to calculate is the hypotenuse. So we’re going to be using the sine ratio. For a given angle 𝜃 in a right triangle, the sine ratio, sin of 𝜃, is equal to the length of the opposite side divided by the length of the hypotenuse. We can substitute the values for this triangle into this definition. 𝜃 is equal to 20 degrees, the opposite is 12 units, and the hypotenuse is this unknown 𝑥. So we have the equation sin of 20 degrees is equal to 12 over 𝑥.

Now, we must be careful here. A really common mistake is to think that the unknown, in this case 𝑥, must always be in the numerator of the fraction, and so to write down instead sin of 20 degrees is equal to 𝑥 over 12. But of course, if we did that, we would be dividing the length of the hypotenuse by the length of the opposite, not the length of the opposite by the length of the hypotenuse. This is a really common mistake, though. So we just need to take our time when substituting the values or expressions for each side of the triangle into the definition of our trigonometric ratios. We now need to solve this equation where 𝑥 appears in the denominator of the fraction, and this will require two steps.

First, we multiply both sides of the equation by our unknown 𝑥. On the left-hand side, we now have 𝑥 sin 20 degrees and on the right-hand side, 12 over 𝑥 multiplied by 𝑥 simplifies to 12. Next, we need to divide both sides of the equation by sin of 20 degrees. Remember, this is just a number, so it’s absolutely fine to do this. This gives 𝑥 is equal to 12 over sin of 20 degrees. Finally, we evaluate on our calculators, giving 35.085. Remember, we must make sure that our calculators are in degree mode in order to give the correct answer. The question specifies that we should give our answer to two decimal places. So we round to 35.09. So by applying the sine ratio in this right triangle, we found that the value of 𝑥 to two decimal places is 35.09.

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